我有一些API需要访问令牌来获得响应。在postman
中,我们使用OAuth 2.0
通过提供客户端用户名和密码来获得访问令牌。以类似的方式,我想获取新的访问令牌。
以下是我目前为止尝试过的示例代码。
import java.io.*;
import java.net.URL;
import java.net.URLEncoder;
import java.util.Map;
import java.lang.reflect.Type;
import javax.net.ssl.HttpsURLConnection;
// Google Gson Libraries used for Json Parsing
import com.google.gson.Gson;
import com.google.gson.reflect.TypeToken;
public class AuthGoogle {
/**
* @param args
* @throws IOException
*/
public static void main(String[] args) throws IOException {
// TODO Auto-generated method stub
String grantType = "client_credentials";
String applicationID = "application";
String username = "username";
String password = "password";
String url = "url_link";
HttpsURLConnection httpConn = null;
BufferedReader in = null;
try {
// Create the data to send
StringBuilder data = new StringBuilder();
data.append("grant_type=" + URLEncoder.encode(grantType, "UTF-8"));
data.append("&client_id=" + URLEncoder.encode(applicationID, "UTF-8"));
data.append("&username=" + URLEncoder.encode(username, "UTF-8"));
data.append("&password=" + URLEncoder.encode(password, "UTF-8"));
// Create a byte array of the data to be sent
byte[] byteArray = data.toString().getBytes("UTF-8");
// Setup the Request
URL request = new URL(null, url, new sun.net.www.protocol.https.Handler());
httpConn = (HttpsURLConnection)request.openConnection();
httpConn.setRequestMethod("POST");
httpConn.setRequestProperty("Content-Type", "application/x-www-form-urlencoded");
httpConn.setRequestProperty("Content-Length", "" + byteArray.length);
httpConn.setDoOutput(true);
// Write data
OutputStream postStream = httpConn.getOutputStream();
postStream.write(byteArray, 0, byteArray.length);
postStream.close();
// Send Request & Get Response
InputStreamReader reader = new InputStreamReader(httpConn.getInputStream());
in = new BufferedReader(reader);
// Get the Json reponse containing the Access Token
String json = in.readLine();
System.out.println("Json String = " + json);
// Parse the Json response and retrieve the Access Token
Gson gson = new Gson();
Type mapType = new TypeToken<Map<String,String>>(){}.getType();
Map<String,String> ser = gson.fromJson(json, mapType);
String accessToken = ser.get("access_token");
System.out.println("Access Token = " + accessToken);
} catch (java.io.IOException e) {
// This exception will be raised if the server didn't return 200 - OK
// Retrieve more information about the error
System.out.println(e.getMessage());
} finally {
// Be sure to close out any resources or connections
if (in != null) in.close();
if (httpConn != null) httpConn.disconnect();
}
}
}
输出为Connection refused: connect.
我尝试过的另一个代码是:-
import org.apache.oltu.oauth2.client.OAuthClient;
import org.apache.oltu.oauth2.client.URLConnectionClient;
import org.apache.oltu.oauth2.client.request.OAuthClientRequest;
import org.apache.oltu.oauth2.client.response.OAuthJSONAccessTokenResponse;
import org.apache.oltu.oauth2.common.OAuth;
import org.apache.oltu.oauth2.common.message.types.GrantType;
import java.io.BufferedReader;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.net.HttpURLConnection;
import java.net.URL;
import org.apache.commons.codec.binary.Base64;
public class OltuJavaClient {
public static final String TOKEN_REQUEST_URL = "url_link";
public static final String CLIENT_ID = "client_id";
public static final String CLIENT_SECRET = "client_pass";
public static void main(String[] args) {
try {
OAuthClient client = new OAuthClient(new URLConnectionClient());
OAuthClientRequest request =
OAuthClientRequest.tokenLocation(TOKEN_REQUEST_URL)
.setGrantType(GrantType.CLIENT_CREDENTIALS)
.setClientId(CLIENT_ID)
.setClientSecret(CLIENT_SECRET)
// .setScope() here if you want to set the token scope
.buildQueryMessage();
request.addHeader("Accept", "application/json");
request.addHeader("Content-Type", "application/json");
request.addHeader("Authorization", base64EncodedBasicAuthentication());
String token = client.accessToken(request, OAuth.HttpMethod.POST, OAuthJSONAccessTokenResponse.class).getAccessToken();
System.out.println(token.toString());
} catch (Exception exn) {
exn.printStackTrace();
}
}
private static String base64EncodedBasicAuthentication() {
// TODO Auto-generated method stub
return null;
}
}
我在这里得到这个错误:-OAuthProblemException{error='unsupported_response_type', description='Invalid response! Response body is not application/json encoded', uri='null', state='null', scope='null', redirectUri='null', responseStatus=0, parameters={}}
我们可以这样做吗?任何线索都将不胜感激。
5条答案
按热度按时间xqk2d5yq1#
使用JAVA 11
java.net.http
获取访问令牌的最佳方法。下面是示例代码:
dtcbnfnu2#
将以下依赖项添加到pom.xml
将下面的java代码添加到try catch块中的类中
vuv7lop33#
基本上,你应该使用
buildBodyMessage
。在内部,所有的头文件,如Content-Type
,Authorization
也可以被删除。请注意,Content-Type
是在调用client.accessToken
时在内部设置的(如headers.put(OAuth.HeaderType.CONTENT_TYPE, OAuth.ContentType.URL_ENCODED);
),因此手动设置Content-Type
将覆盖其值,这将导致请求失败。44u64gxh4#
使用下面提到的代码行在请求体中设置授权类型,肯定可以
sauutmhj5#
我编写了一个适合我的代码。这是: