我编写了一个函数来绘制以下数据的直方图(已缩短)
data_1 =
[0.68417915 0.53041328 0.05499373 0.32483917 0.30501979 0.12136537
0.22964997 0.5837272 0.06000122 0.69908738 0.15690346 0.20363323
0.10390346 0.98658757 0.98359924 0.29493355 0.72561782 0.75613625
0.69628136 0.71322217 0.63060554 0.91118187 0.14915375 0.70929528
0.42408604 0.35388851 0.62253336 0.63676291 0.44358184 0.45063505
0.36477958 0.15807182 0.714753 0.96713497 0.4094859 0.56495619
0.57509395 0.9355384 0.46284749 0.67779101 0.92363017 0.05682404
0.89631817 0.52587218 0.79428246 0.14486141 0.31300898 0.10176549
0.21841843 0.25688406 0.55415834 0.84957183 0.76246304 0.98489949
0.3936749 0.51460251 0.50138111 0.36060756 0.44854838 0.3919771
0.05113578 0.23980216 0.96111616 0.05969004 0.63652018 0.77869691
0.74565952 0.53789898 0.8876854 0.02370424 0.75647449 0.1494505
0.56362217 0.84942793 0.75265825 0.43319662 0.1012875 0.09946243
0.69463561 0.46931918 0.12913483 0.22142044 0.77253391 0.1691685
0.41114265 0.011321 0.41941435 0.28070956 0.65810948 0.58770776
0.68763623 0.36828773 0.70466821 0.8332811 0.12652526 0.16867114
0.59106388 0.56926637 0.87954323 0.62176163 7.35566843e-01
1.00146415e-01 6.68137620e-01 4.39246138e-01
3.75875260e-01 2.12544712e-02 3.68062161e-01 5.35692768e-01
6.50231419e-01 7.51573475e-01 1.43792206e-01 3.51057868e-01
1.77127799e-03 9.88480387e-01 8.73988015e-01 3.78791845e-01
5.89179323e-01 4.05978444e-01 6.88178816e-01 8.73515486e-01
3.66033185e-01 7.98291151e-01 2.30921252e-01 8.68201375e-04
4.92515713e-01 4.56100036e-01 5.66357689e-01 1.18801303e-01
8.15197293e-01 1.90998886e-02 4.91136435e-01 4.90613456e-01
1.31219088e-01 8.44170500e-01 1.72284226e-01 9.48296215e-01
7.36638954e-01 2.23674369e-01 7.46383520e-02 1.56815967e-01
6.14167905e-02 9.55175567e-01 1.74517808e-01 6.16529512e-01
7.02704931e-01 2.17204373e-01 6.78545848e-01 8.99756168e-01
5.28857712e-01 8.34009864e-01 5.87747412e-01 9.01901813e-02
9.94429960e-01 8.20847209e-01 3.88627889e-01 7.99302264e-01
1.19291073e-01 3.92748464e-01 4.84674232e-01 6.86047613e-01
9.09811416e-01 4.11619033e-01 5.22738580e-01 7.87679969e-01
8.31886542e-01 5.75564445e-01 7.03306890e-01 4.37121850e-01
2.17908948e-01 9.27734103e-01 1.69151398e-01 1.02815443e-01
8.86529746e-01 9.12471508e-01 3.62394360e-02 5.75760637e-01
9.02910130e-01 9.46808438e-01 5.22324825e-01 7.41599515e-02
1.67554744e-01 9.67044492e-01 6.41305316e-02 2.02375526e-01
7.87664750e-01 4.10928526e-01 3.75066800e-01 1.02825038e-01
7.99960722e-01 5.15931793e-01 6.07891990e-01 4.22650890e-01
2.50692729e-01 4.76696332e-01 3.42881458e-01 4.56350909e-01
2.21493003e-02 9.22045389e-01 4.31748031e-01 3.67451551e-01]
和下面的代码
def plot_histo(data_list, bin_count):
plt.hist(data_list, bins=bin_count, density= True)
return plt.show()
plot_1 = plot_histo(data_1, 100)
我也想在同一张图上画出这个分布的pdf,但是我真的不知道怎么做,因为我是Python的新手!有什么提示吗?
1条答案
按热度按时间snz8szmq1#
有几种方法可以从样本中估计pdf。
一种方法是使用核密度估计,这可以通过
sns.kdeplot
很容易地完成。另一种方法是拟合已知分布的参数,例如,如果你有理由认为你的数据是高斯分布的话,可以使用scikit-learn
GaussianMixture
。