继承视图最简单的方法是做其他人已经在评论中建议的事情：

var Pannel = Backbone.View.extend({
});

var PannelAdvanced = Pannel.extend({
});

但是正如你在评论中提到的，如果你在Pannel中有一个initialize方法，那么如果你在PannelAdvanced中也有一个initialize方法，它就不会被调用，所以你必须显式调用Pannel的initialize方法：

var Pannel = Backbone.View.extend({
   initialize: function(options){
      console.log('Pannel initialized');
      this.foo = 'bar';
   }
});

var PannelAdvanced = Pannel.extend({
   initialize: function(options){
      Pannel.prototype.initialize.apply(this, [options])
      console.log('PannelAdvanced initialized');
      console.log(this.foo); // Log: bar
   }
});

如果你有很多继承自Pannel的视图，那么你必须记住从所有视图中调用Pannel的initialize方法。更糟糕的是，如果Pannel现在没有initialize方法，但你选择在将来添加它，那么你以后就需要访问所有继承的类并确保它们调用Pannel的initialize。这是定义Pannel的另一种方法，这样您继承的视图就不需要调用Pannel的initialize方法：

var Pannel = function (options) {

    // put all of Panel's initialization code here
    console.log('Pannel initialized');
    this.foo = 'bar';

    Backbone.View.apply(this, [options]);
};

_.extend(Pannel.prototype, Backbone.View.prototype, {

    // put all of Panel's methods here. For example:
    sayHi: function () {
        console.log('hello from Pannel');
    }
});

Pannel.extend = Backbone.View.extend;

// other classes inherit from Panel like this:
var PannelAdvanced = Pannel.extend({

    initialize: function (options) {
        console.log('PannelAdvanced initialized');
        console.log(this.foo);
    }
});

var pannelAdvanced = new PannelAdvanced(); //Log: Pannel initialized, PannelAdvanced initialized, bar
pannelAdvanced.sayHi(); // Log: hello from Pannel

这也是我喜欢使用Coffeescript的原因之一。继承之类的东西要好得多。为了背上@JohnnyO的正确答案，我可以在Coffeescript中说同样的话：

class Panel extends Backbone.View
    initialize: ->
        console.log 'Panel initialized'
        @foo = 'bar'

class PanelAdvanced extends Panel
    initialize: ->
        super
        console.log 'PanelAdvanced initialized'
        console.log @foo

再进一步说：
我喜欢@JohnnyO的方法，但我想确认生成的视图仍然能够完成它应该做的所有事情。考虑到他的方法，我不怀疑会有任何问题，但我想更确定一点。
因此，我花了一分钟的时间，将Backbone.js Views test suite修改为JohnnyO提出的多重继承技术。
您可以在http://jsfiddle.net/dimadima/nPWuG/下运行结果。所有测试均通过。
我的基础视图和扩展视图：

var RegularView = function (options) {
  // All of this code is common to both a `RegularView` and `SuperView`
  // being constructed.
  this.color = options && (options.color || 'Green');

  // If execution arrives here from the construction of
  // a `SuperView`, `Backbone.View` will call `initialize`
  // that belongs to `SuperView`. This happens because here
  // `this` is `SuperView`, and `Backbone.View`, applied with
  // the current `this` calls `this.initialize.apply(this, arguments)`
  Backbone.View.apply(this, arguments)
};

RegularView.extend = Backbone.View.extend;

_.extend(RegularView.prototype, Backbone.View.prototype, {
  // Called if a `RegularView` is constructed`,
  // Not called if a `SuperView` is constructed.
  initialize: function () {
    console.log('RegularView initialized.');
  },

  say_hi: function() {
    console.log('Regular hi!');
  }

});

var SuperView = RegularView.extend({
  // Called if a `SuperView` is constructed`,
  // Not called if a `RegularView` is constructed.
  initialize: function(options) {
    console.log('SuperView initialized.')
  },

  say_hi: function() {
    console.log('Super hi!');
  }
})

对于测试套件，我获取了latest views tests from GitHub，并将出现的Backbone.View替换为RegularView。然后，测试使用RegularView和RegularView.extend()的结果来确保两者都执行了它们应该执行的操作。