我已经通过 AJAX 使用AuthenticationEntryPoint和SimpleUrlAuthenticationSuccessHandler实现了用户身份验证。
现在,我需要将登录用户名输入到脚本变量中。
有人能帮我吗?
我的验证成功处理程序
public class MyAuthenticationSuccessHandler extends SimpleUrlAuthenticationSuccessHandler {
private Log log = LogFactory.getLog(MyAuthenticationSuccessHandler.class);
@Override
public void onAuthenticationSuccess(HttpServletRequest request, HttpServletResponse response,
Authentication authentication) throws IOException, ServletException {
log.info("point-2-->"+authentication.getName()); //this prints what I need.
// This is actually not an error, but an OK message. It is sent to avoid redirects.
response.sendError(HttpServletResponse.SC_OK);
}
}
我的JavaScript函数
$("#login").on('click', function(e) {
e.preventDefault();
$.ajax({url: getHost() + "/j_spring_security_check",
type: "POST",
beforeSend: function(xhr) {
xhr.withCredentials = true;
},
data: $("#loginForm").serialize(),
success: function(response, options) {
// We get a success from the server
//I need to get user name here
},
error: function(result, options) {
// We get a failure from the server...
$(".error").remove();
$('#j_username').before('<div class="error">Login failed, please try again.</div>');
}
});
});
我已经为不同的问题附上了所有相关的文件。请访问下面的链接检查他们。
Spring Security; custom-filter and user-service-ref not working together
1条答案
按热度按时间ifsvaxew1#
我找到了解决办法。
我只是进行了另一个 AJAX 调用,并捕获了登录用户。
我的JavaScript函数
登录用户控制器