我试图从一个python代码中检索节点和链接,它已经有了它们的唯一性,并且是JSON的形式,但是当console.log在浏览器上显示数据时,我无法在屏幕上以forcelayout图形的形式查看它们。大概我不理解在javascript中调用的顺序,所以忍受我缺乏javascript知识。这里的任何帮助都是非常感谢的。
这是一个从画廊借来的例子,当然我篡改了d3.json部分。
<script>
var width = 960,
height = 500;
//force = d3.layout.force().nodes(d3.values(ailments)).links(rels).size([width, height]).linkDistance(60).charge(-300).on("tick", tick).start();
var nodes = {};
var ailments = {} ;
var rels = [];
var force = d3.layout.force().size([width, height]).linkDistance(60).charge(-300).on("tick",tick);
console.log('initiated force!! be with you !!');
d3.json("/getA", function(error, dataset){
console.log('getA the function gets called now ... ');
ailments = dataset.nodes;
//ailments = dataset.nodes['nodes'];
//rels = dataset.links['links'] ;
rels = dataset.links;
console.log(ailments);
//console.log(nodes);
console.log('relationships coming up..');
console.log(rels);
force.start();
});
function tick() {
path.attr("d", linkArc);
circle.attr("transform", transform);
text.attr("transform", transform);
}
force = d3.layout.force().nodes(d3.values(ailments)).links(rels).size([width, height]).linkDistance(60).charge(-300).on("tick", tick).start();
console.log("now i threw the graph out there");
var svg = d3.select("body").append("svg")
.attr("width", width)
.attr("height", height);
svg.append("defs").selectAll("marker")
.data(["suit", "licensing", "resolved"])
.enter().append("marker")
.attr("id", function(d) { return d; })
.attr("viewBox", "0 -5 10 10")
.attr("refX", 15)
.attr("refY", -1.5)
.attr("markerWidth", 6)
.attr("markerHeight", 6)
.attr("orient", "auto")
.attr("stroke", "black")
.append("path")
.attr("d", "M0,-5L10,0L0,5");
// Per-type markers, as they don't inherit styles.
// Use elliptical arc path segments to doubly-encode directionality.
var path = svg.append("g").selectAll("path")
.data(force.links())
.enter().append("path")
.attr("class", function(d) { return "link " + d.type; })
.attr("marker-end", function(d) { return "url(#" + d.type + ")"; });
var circle = svg.append("g").selectAll("circle")
.data(force.nodes())
.enter().append("circle")
.attr("r", 6)
.call(force.drag);
var text = svg.append("g").selectAll("text")
.data(force.nodes())
.enter().append("text")
.attr("x", 8)
.attr("y", ".31em")
.text(function(d) { return d.name; });
function linkArc(d) {
var dx = d.target.x - d.source.x,
dy = d.target.y - d.source.y,
dr = Math.sqrt(dx * dx + dy * dy);
return "M" + d.source.x + "," + d.source.y + "A" + dr + "," + dr + " 0 0,1 " + d.target.x + "," + d.target.y;
}
function transform(d) {
return "translate(" + d.x + "," + d.y + ")";
}
</script>
- 正如我所说,我仍然不清楚这里的顺序,因为这是我第一次尝试javascript!
注意到python和flask标签被删除-我认为这是好的,因为我不认为有一个问题,下面的python代码发送此数据。仅供参考
@app.route("/getA")
def getA():
print('get A gets called ...')
db = get_db()
nodes = []
rels = []
ailment = []
cure = []
jlinks = {"links":[]}
uniqueNodes = {"nodes":[]}
sql = "MATCH (a:Ailment) -[:SOLVED_BY]->(theCURE) return a as ailment, theCURE limit 5"
with db as graphDB_Session:
nodes = graphDB_Session.run(sql)
print("output:")
for node in nodes:
#print(node)
prepare_links(node, ailment, cure)
for idx, value in enumerate(ailment):
#print (ailment[idx], cure[idx])
source = ailment[idx]['title']
target = cure[idx]['title']
y = {"source":source, "target":target, "type":"SOLVED_BY"}
jlinks["links"].append(y)
if (source not in (uniqueNodes["nodes"])):
uniqueNodes["nodes"].append(source)
if (target not in (uniqueNodes["nodes"])):
uniqueNodes["nodes"].append(target)
print(jlinks)
print(uniqueNodes)
return Response(dumps({"nodes": uniqueNodes, "links": jlinks}),mimetype="application/json")
def serialize_ailment(ailment):
return {
"title":ailment["title"]
}
def serialize_cure(cure):
return {
"title":cure["title"]
}
def prepare_links(node, ailment, cure):
#ailment.append(serialize_ailment(node.value("ailment")))
ailment.append(node.value("ailment"))
#cure.append(serialize_cure(node.value("theCURE")))
cure.append(node.value("theCURE"))
忍受一些不需要的代码,评论,因为我基本上已经尝试了几个变种。
1条答案
按热度按时间5jdjgkvh1#
两个错误...我想...
1.在Javascript中,从API调用到另一个数组对象中获取数组的方法也很混乱。
rels =数据集.链接[“链接”];
看起来很明显,但不知何故,我也搞砸了这一点。更新后的脚本,工作在我自己的数据终于这样-
而“提供”这些数据的python代码是这样的...
从技术上讲,我还没有用完来自python函数的唯一节点,但那是另一天的事了:)感谢阅读。