我是MEANJS的新手，我遇到了一个问题，即有一个名为employee的集合，有多个文档的boss字段。现在我想得到所有员工的较低级别。
例如：
1){_id:ObjectId('587dcd3edca5f235f862fdfd'), name:'John'} //he doesn't have boss
2){_id:ObjectId('587dcd3edca5f235f86dddew'), name: 'Jimmy', 'boss': ObjectId('587dcd3edca5f235f862fdfd')} //john is boss
3){_id:ObjectId('587dcd3edca5f235f863ew'), name: 'David', 'boss': ObjectId('587dcd3edca5f235f86dddew')} //john,Jimmy are bosses
4){_id:ObjectId('587dcd3edca5f235f86qwa'), name: 'Dyan', 'boss': ObjectId('587dcd3edca5f235f86dddew')} //john,Jimmy,David are bosses
5){_id:ObjectId('587dcd3edca5f235f8ew32'), name:'Jack', 'boss': ObjectId('587dcd3edca5f235f862fdfd')} //john is boss
6){_id:ObjectId('587dcd3edca5f2wsw23rlot'), name: 'Loren', 'boss':ObjectId('587dcd3edca5f235f8ew32')} //john,Jack is boss
如果我们把

Jonh则输出将为['Jimmy','Jack','David','Dyan','Loren']
插孔则输出将为['Loren']

下面是我的尝试代码：-

getBosses(user._id)
function getBosses(id){
  User.find({boss:id})
      .exec(function(err,users){
        if(err)
           return console.log(err);

        //How handle here 'users' array
       //for something getBosses call recursively

    })
}