序列化存储的json对象会产生空指针hibernate vladmihalcea/hibernate-type

hvvq6cgz  于 2022-11-14  发布在  其他
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我在我的数据库中将一个Java对象保存为json。对于这个实现,当我保存它时,它工作得很好,并且我可以在我的数据库中找到新行。但是,每当我尝试获取存储的同一对象时,我都会收到以下错误:

java.lang.NullPointerException: null
    at java.lang.Class.isAssignableFrom(Native Method)
    at com.vladmihalcea.hibernate.type.json.internal.JsonTypeDescriptor.fromString(JsonTypeDescriptor.java:104)
    at com.vladmihalcea.hibernate.type.json.internal.JsonTypeDescriptor.wrap(JsonTypeDescriptor.java:165)
    at com.vladmihalcea.hibernate.type.json.internal.AbstractJsonSqlTypeDescriptor$1.doExtract(AbstractJsonSqlTypeDescriptor.java:34)
    at org.hibernate.type.descriptor.sql.BasicExtractor.extract(BasicExtractor.java:47)...

我的休眠版本是:

Hibernate Core {5.3.7.Final}
Hibernate Commons Annotations {5.0.4.Final}

我正在使用这个库将我的Java类序列化为json。

com.vladmihalcea:hibernate-types-52:2.17.3

奇怪的是,我可以将实体保存到数据库(可以反序列化),但当我尝试获取对象时,它无法重新构建对象。

@Getter
@Setter
@TypeDefs({
        @TypeDef(name = "json", typeClass = JsonType.class)
})
public class NotificationMessage implements Serializable {
    private Long id;
    private String name = "";
    private String type;
}
@Entity
@Table(name = "notification")
@Getter
@Setter
@EntityListeners(AuditingEntityListener.class)
public class Notification {

    @Id
    @Column(name = "notification_id")
    @GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "id_notification_sequence")
    @SequenceGenerator(name = "id_notification_sequence", sequenceName = "id_notification_sequence", allocationSize = 1)
    private Long id;

    @Column(name = "type", nullable = false)
    @Enumerated(EnumType.STRING)
    @NotNull
    private NotificationType type;

    @NotNull
    @ManyToOne(fetch = FetchType.LAZY)
    @JoinColumn(name = "user_uuid", referencedColumnName = "user_uuid")
    private User user;

    @Type(type = "json")
    @Column(name = "message", columnDefinition = "json")
    @NotNull
    private NotificationMessage message;

    @Column(name = "acknowledged")
    private boolean acknowledged = false;

    @Column(name = "created_date", nullable = false, updatable = false)
    @CreatedDate
    private LocalDateTime createdDate;

    @Column(name = "modified_date")
    @LastModifiedDate
    private LocalDateTime modifiedDate;

    @Override
    public boolean equals(Object o) {
        if (this == o) return true;
        if (o == null || getClass() != o.getClass()) return false;
        Notification that = (Notification) o;
        return id.equals(that.id);
    }

    @Override
    public int hashCode() {
        return Objects.hash(id);
    }
}

以下是我用来获取通知的查询:

@Repository
public interface NotificationRepository extends JpaRepository<Notification, Long>, JpaSpecificationExecutor<Notification> {
    @Query("SELECT n FROM Notification n WHERE n.type = :type AND n.acknowledged = false")
    List<Notification> findAllByTypeAndAcknowledgedIsFalse(@Param("type") NotificationType type);
}
qyzbxkaa

qyzbxkaa1#

您还必须使用@TypeDef注解将Hibernate类型声明为Entity类,如下所示:

@Entity
@Table(name = "notification")
@Getter
@Setter
@EntityListeners(AuditingEntityListener.class)
@TypeDef(name = "json", typeClass = JsonType.class)
public class Notification {

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