在获取处理typescript的reduce函数时遇到了一些困难-类型和返回值-省略了故事书中的一些控件（在标记为ERROR的代码中添加了两个TS错误）
有人能告诉我正确的解决方案吗？我如何删除这些消息？

const controlsToOmit: string[] = [
  'connectedLeft',
  'connectedRight',
];
interface Props {
  accumulator: {
    [key: string]: {
      table: {
        disable: true;
      };
    };
  };
  value: string;
}
const controlsToOmitArgTypes = controlsToOmit.reduce<Props>(
  (accumulator, value) => ({
    ...accumulator,
    [value]: {
      table: {
        disable: true,
      },
    },
  }),
  {} ** Argument of type '{}' is not assignable to parameter of type 'Props' **
);
export default {
  title: 'Components/Buttons/ButtonMeta',
  component: ButtonMetaComponent,
  argTypes: {
    ...controlsToOmitArgTypes, ** Spread types may only be created from object types. **
  },
};

controlsToOmitArgTypes返回以下对象

{
    "connectedLeft": {
        "table": {
            "disable": true
        }
    },
    "connectedRight": {
        "table": {
            "disable": true
        }
    },
}