regex 如何在一个正则表达式中捕获(0/32 LK)(0/21 x)和(3/17)

ih99xse1 于 2022-11-18 发布在其他

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我想清理一些TNM条目，下面是一个示例：

structure(list(TNM = c("pT3 N0 (0/13)", "pT3 N2b (21/45l)", "pT3 N0 (0/32 LK)"
)), class = "data.frame", row.names = c(NA, -3L))

               TNM
1    pT3 N0 (0/13)
2 pT3 N2b (21/45l)
3 pT3 N0 (0/32 LK)

到目前为止我得到了这个：

library(dplyr)
library(stringr)

df %>% 
  mutate(TNM = str_remove_all(TNM, '\\,|\\;|\\.'),
         TNM = str_replace_all(TNM, ' ', ''),
         TNM = str_replace_all(TNM, "x", "X")) %>% 
  mutate(N_count = str_extract(TNM, '\\(\\d+\\/\\d+\\)'))

            TNM N_count
1    pT3N0(0/13)  (0/13)
2 pT3N2b(21/45l)    <NA>
3  pT3N0(0/32LK)    <NA>

这是可行的：

library(dplyr)
library(stringr)

df %>% 
  mutate(TNM = str_remove_all(TNM, '\\,|\\;|\\.'),
         TNM = str_replace_all(TNM, ' ', ''),
         TNM = str_replace_all(TNM, "x", "X")) %>% 
  mutate(N_count = str_extract(TNM, '\\(\\d+\\/\\d+\\)|\\(\\d+\\/\\d+\\w\\)|\\(\\d+\\/\\d+\\w+\\)'))

    TNM  N_count
1    pT3N0(0/13)   (0/13)
2 pT3N2b(21/45l) (21/45l)
3  pT3N0(0/32LK) (0/32LK)

有没有办法缩短这个正则表达式：'\\(\\d+\\/\\d+\\)|\\(\\d+\\/\\d+\\w\\)|\\(\\d+\\/\\d+\\w+\\)'？

regex

来源：https://stackoverflow.com/questions/74275211/how-to-capture-0-32lk-0-21x-and-3-17-in-one-regular-expression