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Scanner is skipping nextLine() after using next() or nextFoo()? (24 answers)
Closed last year.
I have created two files one with having private variables and getters and setters, and other with taking input from the user and displaying the output in the console.
When I execute the program, it runs without error but when the input is given, it takes 3 inputs out of 4.
I am unable to get input for the fourth variable.
File with getters and setters👇
package tryProject;
public class Employee {
private String name;
private int yearJoin;
private int salary;
private String address;
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public int getYearJoin() {
return yearJoin;
}
public void setYearJoin(int yearJoin) {
this.yearJoin = yearJoin;
}
public int getSalary() {
return salary;
}
public void setSalary(int salary) {
this.salary = salary;
}
public String getAddress() {
return address;
}
public void setAddress(String address) {
this.address = address;
}
}File to take input and give output
package tryProject;
import java.util.Scanner;
public class EmployeeInfo {
public static void main(String[] args) {
Employee e = new Employee();
Scanner s = new Scanner(System.in);
System.out.println("Enter details: ");
System.out.println("Name: ");
String input_name = s.nextLine();
e.setName(input_name);
System.out.println(e.getName());
System.out.println("Salary: ");
int input_salary = s.nextInt();
e.setSalary(input_salary);
System.out.println(e.getSalary());
System.out.println("Year of Join: ");
int input_YearJoin = s.nextInt();
e.setYearJoin(input_YearJoin);
System.out.println(e.getYearJoin());
System.out.println("Address: ");
String input_Address = s.nextLine();
e.setAddress(input_Address);
System.out.println(e.getAddress());
}
}
2条答案
按热度按时间sqyvllje1#
我测试过你的程序，它确实打印了姓名、薪水和年份，而地址却打印了一个空行。原因是当你给予“加入年份”时，你输入一些数字，然后按“回车”键。当你按“回车”键时，你实际上给予一个空行（“\n”）这仍然是一个输入，它被地址域接受，这就是为什么程序不等待你的地址行，如果你用调试器，你会注意到的。如果你把
String input_Address = s.nextLine();改成String input_Address = s.next();，然后运行你的程序，你就会明白我的意思了。我建议你在阅读加入年份后加上
scanner.nextLine();，这样程序会读取下一个按“Enter”键产生的空行，然后读取你的实际地址数据。您可以阅读这篇文章以获得更多见解：Scanner is skipping nextLine() after using next() or nextFoo()?
plupiseo2#
尝试使用.next（）而不是.nextLine（）。
我也会把它改成这个名字。
我更改了您的代码，使其正常工作：