javascript 根据第二个数组输入筛选数组结果[duplicate]

tpxzln5u 于 2022-11-20 发布在 Java

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Filter array of objects based on another array in javascript（共10个答案）
6小时前关门了。
我有一个对象数组和一个整数id数组。
我只想在react jsx中拥有id与array匹配的对象数组中的那些条目。
例如：

A = [(0)-> id:'123', name:'john', city:'Newyork']
        [(1)-> id:'345', name:'martin', city:'Tokyo']
        [(2)-> id:'456', name:'lee', city:'Malbonre']
        [(3)-> id:'567', name:'roman', city:'Delhi']
        [(4)-> id:'789', name:'julie', city:'US']

B = [123, 456,567]

我希望得到这样的结果：数组A应该只有

A = [(0)-> id:'123', name:'john', city:'Newyork']
        [(1)-> id:'456', name:'lee', city:'Malbonre']
        [(2)-> id:'567', name:'roman', city:'Delhi']

JavaScript

来源：https://stackoverflow.com/questions/74506276/filter-array-result-based-on-second-array-input

2条答案

按热度按时间

vlju58qv1#

将filter与includes一起使用

const A = [{id:'123', name:'john', city:'Newyork'},
        { id:'345', name:'martin', city:'Tokyo'},
       {id:'456', name:'lee', city:'Malbonre'},
       { id:'567', name:'roman', city:'Delhi'},
       {id:'789', name:'julie', city:'US'}]

const B = [123, 456,567]

const result = A.filter(i => B.includes(Number(i.id)))

console.log(result)

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o4tp2gmn2#

const A = [
    { id: "123", name: "john", city: "Newyork" },
    { id: "345", name: "martin", city: "Tokyo" },
    { id: "456", name: "lee", city: "Malbonre" },
    { id: "567", name: "roman", city: "Delhi" },
    { id: "789", name: "julie", city: "US" }
  ];
  const B = [123, 456, 567];
  const result = A.filter((item, index) => B.includes(Number(item.id)));

https://codesandbox.io/s/new?file=/src/App.js:56-421

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javascript 根据第二个数组输入筛选数组结果[duplicate]

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