我正在使用MUI选择多选选项,并显示一些修改后的最终值作为MUI芯片。现在,当我点击添加芯片不显示在那一瞬间,但如果我改变任何值的名称和后缀的网页渲染,然后芯片显示。也许我错过了什么。任何帮助是感激。
import { useState, } from 'react';
import styled from 'styled-components';
import {OutlinedInput, MenuItem, Chip, useTheme, Select} from '@mui/material';
const ITEM_HEIGHT = 48;
const ITEM_PADDING_TOP = 8;
const MenuProps = {
PaperProps: {
style: {
maxHeight: ITEM_HEIGHT * 4.5 + ITEM_PADDING_TOP,
width: 250,
},
},
};
const EditUser =styled.div`
display: flex;
align-items: center;
justify-content: flex-start;
margin-left:5px;
margin-top: 10px;
margin-bottom: 20px;
`
const Label = styled.label`
width: 100px;
margin: 10px;
`
const LabelInputWrapper = styled.div`
margin-bottom:25px;
flex:1 0 30%;
display: ${(props) => props.disp};
`
const Adduserformcont = styled.div`
display: flex;
flex-wrap:wrap;
margin:10px;
`
const AddChrgWrapper = styled.div`
display: flex;
`
const names = [
'Oliver Hansen',
'Van Henry',
'April Tucker',
'Ralph Hubbard',
'Omar Alexander',
'Carlos Abbott',
'Miriam Wagner',
'Bradley Wilkerson',
'Virginia Andrews',
'Kelly Snyder',
];
function getStyles(name, personName, theme) {
return {
fontWeight:
personName.indexOf(name) === -1
? theme.typography.fontWeightRegular
: theme.typography.fontWeightMedium,
};
}
const desigSuffix = ["I","II", "III", "IV"];
const EditUsers = () => {
const theme = useTheme();
const [personName, setPersonName] = useState([]);
const [value, setValue] = useState({})
const [finalValue, setFinalValue] =useState([])
const onChangeUserForm = (event) => {
if(event.target.name === 'selectMultiAddnCharg'){
setPersonName(event.target.value)
}
let temp = {...value, [event.target.name]:event.target.value}
setValue(temp);
console.log(temp)
}
const addWithSuffix = () => {
let tempArray = finalValue;
tempArray.push(`${value.adnCharge} (${value.desgnSuffix})`)
setFinalValue(tempArray)
}
return (
<>
<form>
<AddChrgWrapper>
<Label>Select name</Label>
<Select
name='selectMultiAddnCharg'
multiple
displayEmpty
value={personName}
onChange={onChangeUserForm}
input={<OutlinedInput />}
renderValue={(selected) => {
if (selected.length === 0) {
return <em>Select name</em>;
}
return selected.join(', ');
}}
MenuProps={MenuProps}
inputProps={{ 'aria-label': 'Without label' }}
>
<MenuItem disabled value="">
<em>Placeholder</em>
</MenuItem>
{names.map((name) => (
<MenuItem
key={name}
value={name}
style={getStyles(name, personName, theme)}
>
{name}
</MenuItem>
))}
</Select>
</AddChrgWrapper>
<LabelInputWrapper name="adnCharge">
<Label>Name</Label>
<select name="adnCharge" onChange={onChangeUserForm}>
<option>Select</option>
{personName.map((item,index) => <option key={index}>{item}</option>)}
</select>
</LabelInputWrapper>
<LabelInputWrapper name="desgnSuffix" >
<Label>Suffix</Label>
<select name="desgnSuffix" onChange={onChangeUserForm}>
<option>Select</option>
{desigSuffix.map((item,index) => <option key={index}>{item}</option>)}
</select>
</LabelInputWrapper>
<button type="button" onClick={(e)=>addWithSuffix(e)}>Add</button>
<div>{finalValue.map((item, index)=><Chip key={index} label={item}/>)}</div>
</form>
</>
)
}
export default EditUsers
1条答案
按热度按时间0ve6wy6x1#
在
addWithSuffix
函数中,当你声明tempArray
时,它不是一个新数组,但你仍然直接改变finalValue
的状态,这是不允许的。state是在应用更改时对组件状态的引用。它不应该直接变化。相反,应该通过基于state的输入构建新对象来表示更改。
可以基于旧状态声明新数组变量
let tempArray = [...finalValue]
或使用
setFinalValue
的第一个参数(旧状态)或
示范:
第一次