您已接近解决方案。
在您找到的元素中，有包含链接的a元素。
这里所需要的只是等待所有这些元素变为可见，获取这些元素的列表，遍历列表并提取链接。
下面的代码是有效的：

from selenium import webdriver
from selenium.webdriver.chrome.service import Service
from selenium.webdriver.chrome.options import Options
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC

options = Options()
options.add_argument("start-maximized")
options.add_argument('--disable-notifications')

webdriver_service = Service('C:\webdrivers\chromedriver.exe')
driver = webdriver.Chrome(options=options, service=webdriver_service)
wait = WebDriverWait(driver, 20)

url = "https://play.google.com/store/apps/dev?id=5305197572942248936"
driver.get(url)

links = wait.until(EC.visibility_of_all_elements_located((By.CSS_SELECTOR, ".ULeU3b a")))
for link in links:
    print(link.get_attribute("href"))

其结果是：

https://play.google.com/store/apps/details?id=com.tatamotors.eguruibcrm
https://play.google.com/store/apps/details?id=com.T1.Primarun
https://play.google.com/store/apps/details?id=com.tata.skoolman
https://play.google.com/store/apps/details?id=com.ttl.tatafleetman