您可以使用撷取群组：

\bAmit Jawaharlaz Daryanani\b.*\n\s*(.*)\n

说明

• \bAmit Jawaharlaz Daryanani\b匹配名称
• .*\n匹配行的其余部分和一个换行符
• \s*(.*)\n匹配可选的空白字符，并捕获组1中的整行，然后匹配换行符

请参阅regex demo和Python demo。

import re

pattern = r"\bAmit Jawaharlaz Daryanani\b.*\n\s*(.*)\n"

s = ("Amit Jawaharlaz Daryanani,  Evercore ISI Institutional Equities, Research Division - Senior MD & Fundamental Research Analyst   [19]\n"
     " I have 2 as well. I guess, first off, on the channel inventory, I was hoping if you could talk about how did channel inventory look like in the March quarter because it sounds like it may be below the historical ranges. And then the discussion you had for June quarter performance of iPhones, what are you embedding from a channel building back inventory levels in that expectation?\n"
     " \n")

m = re.search(pattern, s)
if m:
    print(m.group(1))

输出量

I have 2 as well. I guess, first off, on the channel inventory, I was hoping if you could talk about how did channel inventory look like in the March quarter because it sounds like it may be below the historical ranges. And then the discussion you had for June quarter performance of iPhones, what are you embedding from a channel building back inventory levels in that expectation?

试试这个：

• 名称的非捕获组
• 查找第一个\n
• 捕获组直到第二个\n

re.findall(r'(?:Amit Jawaharlaz Daryanani).*?\n(.*?)\n', text)

这是因为.*?是非贪婪的，这意味着它在遇到第一个\n之前停止。
输出量：

[' I have 2 as well. I guess, first off, on the channel inventory, I was hoping if you could talk about how did channel inventory look like in the March quarter because it sounds like it may be below the historical ranges. And then the discussion you had for June quarter performance of iPhones, what are you embedding from a channel building back inventory levels in that expectation?']