我正在努力尝试把这个从python转换成c++，如果有人能帮忙的话，我将不胜感激。假设timern和Day变量已经给出，所以不需要time.ctime（thing）

if Day!=4:
    timeschedule=["08:30","09:20","10:10","11:00","11:30","12:20","13:10","14:00","14:45"]
else:
    timeschedule=["08:30","09:20","09:50","10:40","11:30"]
timern=time.ctime()[11:16]

for i in timeschedule:
    if timern<i:
        Finishes=i
        Period=timeschedule.index(Finishes)+1
        break
    else:
        continue

timern=timedelta(hours=int(timern[0:2]), minutes=int(timern[3:5]))
Finishes=timedelta(hours=int(Finishes[0:2]), minutes=int(Finishes[3:5]))

TimeLeft= Finishes-timern

seconds = TimeLeft.total_seconds()
hours = seconds // 3600
minutes = (seconds % 3600) // 60
seconds = seconds % 60
DayL=Days[Day]
Output=str(minutes)[0:2]+" minutes left till "+DayL[Period]

以下是我的转换尝试：

if (getCurrentDOWAsString=="Saturday" || getCurrentDOWAsString=="Sunday") {
  break;
}
else if (getCurrentDOWAsString=="Friday") {
  static const char *TimeSchedule[5] = {"08:30","09:20","09:50","10:40","11:30"};
}
else {
  static const char *TimeSchedule[9] = {"08:30","09:20","10:10","11:00","11:30","12:20","13:10","14:00","14:45"};
}

int Cn=0;
for (std::list<TimeSchedule>::iterator it = data.begin(); it != data.end(); ++it){
    std::cout << it->name;
    int Cn=Cn+1;
    if (CTime < it) {
      char Finishes=it;
      int Period=Cn;
      break;    
}
int FinH = Finishes.substr(0,2);
int FinM = Finishes.substr(3,2);
if(FinM.minutes > minutes.minutes) {
  --hours.hours;
  minutes.inutes += 60;
}
  difference->minutes = minutes.minutes-FinM.minutes;
  difference->hours = hours.hours-FinH.hours;
  char TL = char(difference->hours)+":"+char(difference->minutes)

我总是在这里得到一个错误（std：：list：：iterator it = data.开始（）;如果您有一个数据库，那么您就可以使用它。it）特别是部分，我不知道为什么。这部分代码是从网上的一个简短教程中提取的，但我还没有完全掌握它的思想，这是我挣扎的地方。