在名为removeStopWords的函数中，有一个名为original_words的数组，还有一个名为stop_words的数组，我想打印original_words中所有不存在于stop_words中的元素
下面是我的代码，我尝试使用多个条件使用嵌套循环，但它们不起作用：

#include <iostream>
#include <string>

using namespace std;
void removeStopWords(string str);

int main()
{
    string str;
    cout<<"String : ";
    getline(cin, str);
    removeStopWords(str);
    return 0;
}

void removeStopWords(string str)
{
    string stop_words[10] = { "this" , "is " , "a" , "are" , "and" , "as" , "at" , "do" , "hence" , "your"};
    string out[1000] ;
    string original_words[1000] ;
    int length = str.size();
    int BreakWordIndex = 0;
    int index_out = 0;
    string temp;
    int count = 0;

    int number_of_words = 1;
    //loop to counter number of words in the input string
    for(int x = 0; x<length; x++)
    {
        if(str[x] == 32)
        {
            number_of_words++;
        }
    }
    //loop to put all the words of the string in an array
    for ( int i = 0; i<length; i++)
    {
        if(str[i] == 32)
        {
            index_out++;
        }
        else
        {
            original_words[index_out] += str[i];//this
            
        }
        
    }
    //tester loop
    for(int i = 0; i<number_of_words; i++)
    {
        for(int j = 0; j<10; j++)
        {
            if(original_words[i] != stop_words[j])
            {
                out[i] = original_words[i];
            }
        }
        // out[count] = original_words[i];
    }
    // cout<<count;

    for ( int i = 0; i<10; i++)
    {
        cout<<out[i]<<" ";
    }
}