我不会去Pandasudfs，诉诸udfs它不能在pyspark中完成。无论如何，代码为以下两者

df = spark.read.load('/databricks-datasets/asa/small/small.csv', header=True,format='csv')

sf = df.select(df.colRegex("`.*rrDelay$|.*pDelay$`"))

#sf.show()

columns = ["id","ArrDelay","DepDelay"]
data = [("a", 81.0,3),
    ("b", 36.2,5),
    ("c", 12.0,5),
    ("d", 81.0,5),
    ("e", 36.3,5),
    ("f", 12.0,5),
    ("g", 111.7,5)]

sf = spark.createDataFrame(data=data,schema=columns)

sf.show()

# Use aggregate function
new = (sf.withColumn('sums', array(*[x for x in ['ArrDelay','DepDelay'] ]))#Create an array of values per row on desired columns
       .withColumn('sums', expr("aggregate(sums,cast(0 as double), (c,i)-> c+i)"))# USE aggregate to sum
      ).show()

#use pandas udf
sch= sf.withColumn('v', lit(90.087654623)).schema
def sum_s(iterator: Iterator[pd.DataFrame]) -> Iterator[pd.DataFrame]:
    for pdf in iterator:
           
      yield pdf.assign(v=pdf.sum(1))

sf.mapInPandas(sum_s, schema=sch).show()

下面是一个简单方法

from pyspark.sql import functions as F
from pyspark.sql.types import *
from pyspark.sql import Window
from functools import reduce

df = spark.createDataFrame(
    [
        (5,3,2),
        (1,7,0),        
    ],
    ["A", "B", "C"],
)

cols = df.columns
calculate_sum = reduce(lambda a, x: a+x, map(col, cols))

df = (
    df
    .withColumn(
        "sum",calculate_sum
    )
)

df.show()

输出：

+---+---+---+---+
|  A|  B|  C|sum|
+---+---+---+---+
|  5|  3|  2| 10|
|  1|  7|  0|  8|
+---+---+---+---+