I have an asp.net core web api that I created from the wizard - and it's generated code like this:

public static void Main(string[] args)
        {
            var builder = WebApplication.CreateBuilder(args);

            // Add services to the container.
            builder.Services.AddAuthorization();

            // Learn more about configuring Swagger/OpenAPI at https://aka.ms/aspnetcore/swashbuckle
            builder.Services.AddEndpointsApiExplorer();
            builder.Services.AddSwaggerGen();

            var app = builder.Build();

            // Configure the HTTP request pipeline.
            if (app.Environment.IsDevelopment())
            {
                app.UseSwagger();
                app.UseSwaggerUI();
            }
    ...

如果我运行它，我会得到一个swagger url，我可以去

https://localhost:7100/swagger/v1/swagger.yaml

然后得到一个yaml文件......那就好了。
"问题"
但是，由于各种原因，我在CI/CD进程中需要那个yaml文件，所以我希望在构建之后动态地获取它，但是启动Web服务器，调用它，我想做的是创建一个命令行选项来获取swagger文件，该文件不会启动监听http的程序，所以我可以运行"dotnet run myApi generate_swagger_yaml〉比如说：

public static void Main(string[] args)
{
   if (args[0] == "generate_swagger_yaml")
   {
        var yamlFile = ....somehow get the swagger yaml file...
        Console.Writeline( yamlfile );
        return 0;
   }
   ...

但我不知道该怎么做。