windows 如何在井字游戏中重置数组

wn9m85ua  于 2022-11-30  发布在  Windows
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大家好，我是一个新的C，我正试图使我的大学项目井字游戏，我正在努力如何重置我的阵列在我的游戏中，每次我再次玩它不重置阵列，有人能帮助我吗？（为我糟糕的英语sry）
下面是代码：

  1. `#include <stdio.h>
  2. #include <conio.h>
  3. #include <stdlib.h>
  5. char space[3][3] = {
  6.     {'1','2','3'},
  7.     {'4','5','6'},
  8.     {'7','8','9'}
  9. };
  11. void board();
  12. int checkWin();
  13. int game();
  14. void reset();
  18. int main(){
  20.     int choice = -1;
  22.     do{
  23.         printf("\n\n\n\n\n\n\n\t\t\t  ================\n");
  24.         printf("\t\t\t     Tic Tac Toe\n");
  25.         printf("\t\t\t  ================\n");
  26.         printf("\t\t     -----------Menu-----------\n\n");
  27.         printf("\t\t     1. Play\n");
  28.         printf("\t\t     2. Exit\n");
  29.         scanf("%d", &choice);
  30.         switch(choice){
  31.             case 1: game();
  32.                 break;
  33.             case 2: printf("Goodbye!!");
  34.                 exit(0);
  35.                 break;
  36.             default: printf(".......Wrong Key !.......Try Again!......");
  37.                 break;
  38.         }
  40.     }while(choice != 0);
  41. }
  43. int game(){
  44.     int player = 1, i, choice;
  46.     char mark;
  48.     
  49.     do
  50.     {
  51.         system("cls");
  52.         board();
  53.         player = (player % 2) ? 1 : 2;
  55.         printf("Player %d, enter a number:  ", player);
  56.         scanf("%d", &choice);
  58.         mark = (player == 1) ? 'X' : 'O';
  60.         if (choice == 1)
  61.             space[0][0] = mark;
  62.             
  63.         else if (choice == 2)
  64.             space[0][1] = mark;
  65.             
  66.         else if (choice == 3)
  67.             space[0][2] = mark;
  68.             
  69.         else if (choice == 4)
  70.             space[1][0] = mark;
  71.             
  72.         else if (choice == 5)
  73.             space[1][1] = mark;
  74.             
  75.         else if (choice == 6)
  76.             space[1][2] = mark;
  77.             
  78.         else if (choice == 7)
  79.             space[2][0] = mark;
  80.             
  81.         else if (choice == 8)
  82.             space[2][1] = mark;
  83.             
  84.         else if (choice == 9)
  85.             space[2][2] = mark;
  86.             
  87.         else
  88.         {
  89.             printf("Invalid move ");
  91.             player--;
  92.             getch();
  93.         }
  94.         i = checkWin();
  96.         player++;
  97.     }while (i ==  - 1);
  98.     
  99.     board();
  100.     reset();
  101.     
  102.     if (i == 1)
  103.         printf("==>\aPlayer %d win \n\n", --player);
  104.         
  105.     else
  106.         printf("==>\aGame draw\n\n");
  107.     
  108.     getch();
  110.     return 0;
  111. }
  113. int checkWin(){
  115.     if (space[0][0] == space[0][1] && space[0][1] == space[0][2])
  116.         return 1;
  117.         
  118.     else if (space[1][0] == space[1][1] && space[1][1] == space[1][2])
  119.         return 1;
  120.         
  121.     else if (space[2][0] == space[2][1] && space[2][1] == space[2][2])
  122.         return 1;
  123.         
  124.     else if (space[0][0] == space[1][0] && space[1][0] == space[2][0])
  125.         return 1;
  126.         
  127.     else if (space[0][1] == space[1][1] && space[1][1] == space[2][1])
  128.         return 1;
  129.         
  130.     else if (space[0][2] == space[1][2] && space[1][2] == space[2][2])
  131.         return 1;
  132.         
  133.     else if (space[0][0] == space[1][1] && space[1][1] == space[2][2])
  134.         return 1;
  135.         
  136.     else if (space[0][2] == space[1][1] && space[1][1] == space[2][0])
  137.         return 1;
  138.         
  139.     else if (space[0][0] != space[0][0] && space[0][1] != space[0][1] && space[0][2] != space[0][2] &&
  140.         space[1][0] != space[1][0] && space[1][1] != space[1][1] && space[1][2] != space[1][2] && space[2][0] 
  141.         !=  space[2][0] &&  space[2][1] != space[2][1] && space[2][2] != space[2][1])
  143.         return 0;
  144.     else
  145.         return  - 1;
  147. }
  149. void reset(){
  151.     for (int i = 0; i < 3; i++)
  152.     {
  153.         for (int j = 0; j < 3; j++)
  154.         {
  155.             space[i][j] = 0;
  156.         }
  157.         
  158.     }
  159.     
  161. }
  163. void board(){
  165.     system("cls");
  166.     printf("\n\n\tTic Tac Toe\n\n");
  168.     printf("Player 1 (X)  -  Player 2 (O)\n\n\n");
  170.     printf("     |     |     \n");
  171.     printf("  %c  |  %c  |  %c \n", space[0][0], space[0][1], space[0][2]);
  173.     printf("_____|_____|_____\n");
  174.     printf("     |     |     \n");
  176.     printf("  %c  |  %c  |  %c \n", space[1][0], space[1][1], space[1][2]);
  178.     printf("_____|_____|_____\n");
  179.     printf("     |     |     \n");
  181.     printf("  %c  |  %c  |  %c \n", space[2][0], space[2][1], space[2][2]);
  183.     printf("     |     |     \n\n");
  184.     
  186. }`

我尝试使用for循环，但它不工作，我如何解决这个问题？

  1. `void reset(){
  3.     for (int i = 0; i < 3; i++)
  4.     {
  5.         for (int j = 0; j < 3; j++)
  6.         {
  7.             space[i][j] = 0;
  8.         }
  9.         
  10.     }
  11.     
  13. }`
windows

1条答案

按热度按时间
y53ybaqx

y53ybaqx1#

我在C语言中并不流畅，但这不起作用：

  1. char resetted[3][3] = {
  2.  {'0','0','0'},
  3.  {'0','0','0'},
  4.  {'0','0','0'}
  5. };
  7. void reset(){
  8.     space = resetted;
  9. }
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