python-3.x 运行循环10，000次，以测试预期值

iyfjxgzm 于 2022-12-05 发布在 Python

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玩一个2人游戏，玩家A和B轮流从袋子里取出石头。
10颗宝石，9颗白色，1颗黑色
如果你抽到黑石头，你就输了。
假设你轮流抽石头，先走是优势、劣势还是中性？
我知道这可以用条件概率来解决，但我也想用大量的样本数据来证明这一点

import random
import os
import sys

stones = 4
player1Wins = 0
player2Wins = 0

no_games = 100000
gameCount = 0

fatal_stone = random.randint(1, int(stones))

picked_stone = random.randint(1, int(stones))

def pick_stone(self, stones):
    for x in range(1, int(stones) + 1):
        if picked_stone == fatal_stone:
            if (picked_stone % 2) == 0:
                player2Wins += 1 print("Player 2 won")
                break
            if (picked_stone % 2) == 1:
                player1Wins += 1
                print("Player 1 won")
                break
            else:
                stones -= 1 picked_stone = random.randint(1, int(stones))
            self.pick_stone()

pick_stone()

# def run_games(self, no_games): #for i in range(1, int(no_games) + 1): #gameCount = i #self.pick_stone()

print(fatal_stone)
print(picked_stone)

print(int(fatal_stone % 2))
print(int(picked_stone % 2))

print(gameCount)
print("Player 1 won this many times: " + str(player1Wins))
print("Player 2 won this many times: " + str(player2Wins))

python-3.x

来源：https://stackoverflow.com/questions/74651942/running-a-loop-10-000-times-in-order-to-test-expected-value

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按热度按时间

jmp7cifd1#

下面的代码是有效的，它表明无论谁先玩，双方获胜的机会都是相等的。

import random
import os
import sys

num_stones = 4

no_games = 100000

player1Wins = 0
player2Wins = 0

def pick_stone(player: int, stones: list, fatal_stone: int):
    global player1Wins, player2Wins
    
    picked_stone = random.choice(stones)
    stones.remove(picked_stone)
    if (picked_stone == fatal_stone):
        if player == 1:
            player2Wins += 1
        else:
            player1Wins += 1
        return False
    return True


def run_games(no_games: int): 
    for _ in range(no_games): 
        stones = [i for i in range(num_stones)]
        fatal_stone = random.choice(stones)
        
        # player 1 and 2 pick stones in turn
        player = 1
        playing = True
        while playing:
            playing = pick_stone(player, stones, fatal_stone)
            player = player % 2 + 1

    print(f"Total rounds: {no_games}")
    print("Player 1 won this many times: " + str(player1Wins))
    print("Player 2 won this many times: " + str(player2Wins))

run_games(no_games)

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python-3.x 运行循环10，000次，以测试预期值

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