使用strings.Split函数

email := "learning@gmail.com"
    split := strings.Split(email, "@")
    split = strings.Split(split[1], ".")
    fmt.Println("Domain:", split[0])
    fmt.Println("TLD:", split[1])

或者，您可以使用mail.ParseAddress函数验证电子邮件字符串

email := "learning@gmail.com"
    addr, err := mail.ParseAddress(email)
    if err != nil {
        log.Fatal(err)
    }

如果TLD类似于co.id，输出是否仍为co.id？- @zacharyy
只需尝试找到.（strings.Index）的第一个index，并使用1分隔字符串

email := "learning@gmail.co.id"
    split := strings.Split(email, "@")
    index := strings.Index(split[1], ".")
    fmt.Println("Domain:", split[1][:index])
    fmt.Println("TLD:", split[1][index+1:])

或者使用regexp.Split函数

email := "learning@gmail.co.id"
    split := strings.Split(email, "@")
    split = regexp.MustCompile("[.]").
        Split(split[1], 2)
    fmt.Println("Domain:", split[0])
    fmt.Println("TLD:", split[1])

或字符串。SplitN

email := "learning@gmail.co.id"
    split := strings.Split(email, "@")
    split = strings.SplitN(split[1], ".", 2)
    fmt.Println("Domain:", split[0])
    fmt.Println("TLD:", split[1])

或弦。切

_, host, found := strings.Cut(email, "@")
    if !found {
        t.Fatal("fail cut to host (Domain + TLD)")
    }
    domain, tld, found := strings.Cut(host, ".")
    if !found {
        t.Fatal("fail cut to Domain and TLD")
    }
    fmt.Println("Domain:", domain)
    fmt.Println("TLD:", tld)

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