我无法摆脱这个问题,而与gulp文件TypeError:无法读取未定义的属性(阅读'pipe')

nlejzf6q  于 2022-12-08  发布在  Gulp
关注(0)|答案(1)|浏览(195)

我试图为未来的项目设置我的gulpfile,在第一阶段遇到了一个问题,无论我用我的代码做什么都伴随着我:这就是:

"TypeError: Cannot read properties of undefined (reading 'pipe')
    at pipe (D:\HTML\NodeJs\Gulp\src\node_modules\pump\index.js:56:15)
    at Array.reduce (D:\HTML\NodeJs\Gulp\src\node_modules\ometa\lib.js:101:9)
    at pump (D:\HTML\NodeJs\Gulp\src\node_modules\pump\index.js:79:11)
    at Pumpify.setPipeline (D:\HTML\NodeJs\Gulp\src\node_modules\pumpify\index.js:39:5)
    at new Pumpify (D:\HTML\NodeJs\Gulp\src\node_modules\pumpify\index.js:15:30)
    at Function.Pumpify [as obj] (D:\HTML\NodeJs\Gulp\src\node_modules\pumpify\index.js:13:44)
    at globStream (D:\HTML\NodeJs\Gulp\src\node_modules\glob-stream\index.js:73:18)
    at Gulp.src (D:\HTML\NodeJs\Gulp\src\node_modules\vinyl-fs\lib\src\index.js:24:5)
    at operationsWithJsFiles (D:\HTML\NodeJs\Gulp\src\gulpfile.js:23:12)
    at bound (node:domain:421:15)"

我的代码:

// Importing gulp modules
let {Gulp,parallel,dest,series,src, tree} = require('gulp')

let cleanCss = require('clean-css')

let uglify = require('gulp-uglify')

let scss = require('gulp-scss')(require('scss'))

let concat = require('gulp-concat')

let autoprefixer = require('gulp-autoprefixer')

let path = require('path')

let rename = require('gulp-rename')

// Minimizing js files

function operationsWithJsFiles(){

    return src('js/*.js',[{allowEmpty:true}])
    .pipe(uglify())
    .pipe(rename({
        extname:'.min.js'
    }))
    .pipe(concat('AllJs.js'))
    .pipe(dest('../Dist'))
}


// Minimizing scss files

function operationsWithScssFiles(){

    return src('scss/*.scss')
    .pipe(scss())
    .pipe(autoprefixer({
        cascade:false
    }))
    .pipe(rename({
        extname:'.min.css'
    }))
    .pipe(concat('AllCss.css'))
    .pipe(dest('../Dist'))
}

exports.default = parallel(operationsWithJsFiles,operationsWithScssFiles)

P.s:我检查了我的目录正确,所以,我相信,gulp没有问题找到文件P. p. s:我的目录路径可能看起来混乱和滑稽xD

w6mmgewl

w6mmgewl1#

更改此行:

return src('js/*.js',[{allowEmpty:true}])

return src('js/*.js',{allowEmpty:true})

你可能被

src(globs, [options])

在文档中,gulp.src签名
但是,签名中的[]只是表示该参数是 optional,选项实际上并没有放在括号中,所以options只是一个{}对象。

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