这应该可以实现此目的，但您需要提供一个字符串

suffix="1"
x = "The most comment log in coding is Hello World"
for i in re.finditer('[A-Z][a-z]+', x):
    x = x.replace(i.group(), f"{i.group()}{suffix}")
print(x)

输出

The1 most comment log in coding is Hello1 World1

看起来您只希望在单词以大写字母开头的地方附加值，这是一个假设，但如果是这样的话，类似这样的东西将是合适的;

import regex as re
startingString = "The most comment log in coding is Hello World"
appendedValue = "1"
pattern = re.compile(r'\b[A-Z]\w*\b')
print(pattern.sub(r'\g<0>'+appendedValue, startingString))

输出量：

The1 most comment log in coding is Hello1 World1

您可以使用\g<0>来引用完全匹配，然后在它后面追加1。

import re
s = "The most comment log in coding is Hello World"
print(re.sub(r"[A-Z][a-z]+", r"\g<0>1", s))

输出量

The1 most comment log in coding is Hello1 World1