我在Tkinter上构建了一个项目中的两个窗口：1.登录/安全用户界面，接受登录名和密码。有一个“登录”按钮链接到类的方法，检查名称/密码对，如果登录数据正确，则返回True。2.主应用程序用户界面。
所以问题是：输入正确的用户名和密码并按下按钮“登录”（这部分工作正常，因为我进入了正确的IF部分，方法返回True）后，本应调用主UI窗口，但没有发生任何事情。手动关闭登录窗口后，Tkinter引发错误。
我的登录界面代码：

class Security:
    def __init__(self):
        # -------- Window arrangement ------------------- #
        self.root = Tk()
        self.root.title("Gym Activity Tracker")
        self.root.minsize(600, 300)
        self.security_passed = False
        self.user_name = None
        # -------- IMG/(Banner) placing ----------------- #
        self.canvas = Canvas(width=600, height=156)
        self.image = PhotoImage(file="images/divide.png")
        self.canvas.create_image(300, 78, image=self.image)
        self.canvas.config(highlightthickness=0)
        self.canvas.grid(column=0, row=0, columnspan=4)
        # --------- Login labels ---------- #
        self.user_label = Label(text="User: ")
        self.user_label.grid(column=0, row=1, pady=(20, 5))
        self.password_label = Label(text="Password: ", padx=50)
        self.password_label.grid(column=0, row=2, pady=(0, 10))
        self.info_label = Label(text="(Optional)", anchor="e")
        self.info_label.grid(column=2, row=2)
        # --------- Login Buttons ---------- #
        self.add_user = Button(text="➕ Add User", command=self.add_user)
        self.add_user.grid(column=2, row=1, pady=(20, 0))
        self.login_button = Button(text="Login", width=25, command=self.security_check)
        self.login_button.grid(column=1, row=3)
        # --------- Login Entries ---------- #
        self.user_name_var = StringVar(self.root)
        self.user_name_var.set("Choose an User")
        self.user_drop_list = OptionMenu(self.root, self.user_name_var, "sdf")
        self.user_drop_list.config(width=24)
        self.user_drop_list.grid(column=1, row=1, pady=(20, 5))
        self.password_entry = Entry(width=30)
        self.password_entry.grid(column=1, row=2)

        self.root.mainloop()

    def security_check(self):
        """Method validates the user's name and password (if applied) entered
        and returns True if security check has been passed"""
        user_name_entered = self.user_name_var.get()
        user_password_entered = self.password_entry.get()

        data = pd.read_csv("settings/users_list.csv")
        database_user_pass = data.loc[data.name == f"{user_name_entered}", "password"]
        if (f"{user_name_entered}" in data["name"].values) and (str(database_user_pass[1]) == user_password_entered):
            return True

        elif f"{user_name_entered}" not in data["name"].values:
            tkinter.messagebox.showwarning(
                title="Username error",
                message="User does not exist. Please check a spelling or create a new user"
            )
            return False

        elif str(database_user_pass) == user_password_entered:
            tkinter.messagebox.showwarning(
                title="Password error",
                message="Password is not correct for this user"
            )
            return False

        else:
            print("Something went wrong with Security Check")
            return False

它可以从www.example.com上运行main.py：

from frames.security import Security
from frames.ui import MainInterface

def main():
    authorization = Security()
    if authorization.security_check():
        app = MainInterface()

想法是通过运行security_check（）方法对用户进行授权，如果成功，则打开主用户界面。但却得到错误：

Traceback (most recent call last):
  File "C:\Users\kosan\OneDrive\Documents\Python\Projects\personal-gym-tracker\main.py", line 17, in <module>
    main()
  File "C:\Users\kosan\OneDrive\Documents\Python\Projects\personal-gym-tracker\main.py", line 6, in main
    if authorization.security_check():
       ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
  File "C:\Users\kosan\OneDrive\Documents\Python\Projects\personal-gym-tracker\frames\security.py", line 106, in security_check
    user_password_entered = self.password_entry.get()
                            ^^^^^^^^^^^^^^^^^^^^^^^^^
  File "C:\Users\kosan\AppData\Local\Programs\Python\Python311\Lib\tkinter\__init__.py", line 3099, in get
    return self.tk.call(self._w, 'get')
           ^^^^^^^^^^^^^^^^^^^^^^^^^^^^
_tkinter.TclError: invalid command name ".!entry"

提前感谢您的帮助！
我尝试将.destroy（）方法添加到security_check（）方法的IF部分。预期.destroy（）将关闭Security类的主循环并允许MainInterface类中的新主循环运行，但未成功。由于某种原因，它引发了与self.password_entry.get（）相关的错误，但在www.example.com中未调用此值main.py，并且在该行调用“if www.example.com _检查（）"。