c++ cin.ignore()不延迟第一次通过循环的输入

6l7fqoea  于 2022-12-15  发布在  其他
关注(0)|答案(1)|浏览(143)

我正在尝试编写一个版本的Picolo移动的饮酒游戏应用程序,供我和我的朋友们玩(它看起来很简单,我们厌倦了应用程序中的问题,所以我们希望能够编写自己的问题)。它的工作方式应该是提示玩家的数量,随机化问题的顺序,然后一个接一个地问。我试着使用cin.ignore()来等待下一个问题,直到用户按下回车键。除了第一次迭代之外,它对每次迭代都有效。下面是源代码:

#include<iostream>
using std::cin;
using std::cout;
using std::endl;
#include<algorithm>
using std::random_shuffle;
#include<fstream>
using std::ifstream;
#include<cstdlib>
#include<string>
using std::string;
#include<time.h>
const int numQuestions = 19;
int vir6rounds;
bool activeVir6 = false;
int v6counter = 0;

void getQuestion(int questionNumber, string players[], int numPlayers);
int getRandom();

int main()
{
  srand(time(0));
  // Create array of player names based on entered size
  cout << "Enter \"quit\" to end game" << endl;
  cout << "How many players?" << endl;
  int numPlayers;
  cin >> numPlayers;
  cout << "Enter players' names: " << endl;
  string players[numPlayers];
  for (int i = 0; i < numPlayers; i++)
    cin >> players[i];
  bool loop = true;
  int qArray[numQuestions];
  // Populate array
  for (int i = 0; i < numQuestions; i++)
  {
    qArray[i] = i;
  }
  while (loop)
  {
    // Reshuffle array each time game is looped
    random_shuffle(qArray, qArray + numQuestions);
    for (int i = 0; i < numQuestions; i++)
    {
      // Choose 3 random player names from array
      // Changes each time a new question is generated
      random_shuffle(players, players + numPlayers);
      getQuestion(qArray[i], players, numPlayers);
      cin.ignore();                                                     // Problem here
    }
    cout << "Game over; press enter to play again" << endl;
    cin.ignore();
  }
}

void getQuestion(int questionNumber, string players[], int numPlayers)
{

  if (activeVir6 == true)
  {
    v6counter++;
    if (v6counter == vir6rounds)
    {
      cout << "Pong loser can speak again." << endl;
      cin.ignore();
      activeVir6 = false;
      v6counter = 0;
    }
  }
  string player1 = players[0];
  string player2 = players[1];
  string player3 = players[2];
  switch (questionNumber)
  {
  case 0:
    cout << "Going around, Play rock paper scissors with the player to your left." << endl;
    cout << "Losers take two drinks." << endl;
    break;
  case 1:
    cout << player1 << ", who would win in a fight? " << player2 << " or " << player3 << "?";
    cin.ignore();
    cout << "Loser takes two drinks." << endl;;
    break;
  case 2:
    cout << player1 << " chooses the next song" << endl;
    break;
  case 3:
    cout << "Whoever took a shower the least recently has to take a drink" << endl;
    break;
  case 4:
    cout << player1 << ", take as many penalties as you want.";
    cin.ignore();
    cout << "However many you took, " << player2 << " has to take double." << endl;
    break;
  case 5:
    cout << "Everyone switch drinks to the left" << endl;
    break;
  case 6:
    cout << "virus: " << player1 << " versus " << player2 << " in pong." << endl;
    cout << "loser can't speak until otherwise" << endl;
    activeVir6 = true;
    vir6rounds = getRandom();
    break;
  case 7:
    cout << player1 << " take as many penalties as the youngest players age.\nIf you're the youngest, everyone else take 2." << endl;
    break;
  case 8:
    cout << player1 << ", buy " << player2 << " a red bull or take 15 penalties" << endl;
    break;
  case 9:
    cout << player1 << ", let " << player2 << " look through your snap memories or take 8 penalties" << endl;
    break;
  case 10:
    cout << player1 << " has to say yes to " << player2 << " for 5 minutes or take 8 penalties" << endl;
    break;
  case 11:
    cout << player1 << ", show off ur best cartwheel" << endl;
    break;
  case 12:
    cout << player1 << ", change clothes with " << player2 << " or they pick how many penalties you take" << endl;
    break;
  case 13:
    cout << player1 << ", pick someone new to go on aux or they take 5 penalties" << endl;
    break;
  case 14:
    cout << player1 << ", cook " << player2 << " a meal or take 9 penalties" << endl;
    break;
  case 15:
    cout << player1 << ", pick two people to shotgun" << endl;
    break;
  case 16:
    cout << player1 << ", let " << player2 << " paint ur nails or take 10 penalties" << endl;
    break;
  case 17:
    cout << player1 << ", every time you talk to " << player2 << " take 3 penalties until otherwise" << endl;
    break;
  case 18:
    cout << player1 << ", kill yourself or take a penalty." << endl;
    break;
  default:
    cout << "question has not been defined yet" << endl;
  }
  return;
}

下面是一些示例输入。其他一切似乎都运行良好;我遇到的唯一问题是,在输入名字之后,程序在正确工作之前同时打印前两行(在本例中,“helen,buy john a red bull or take 15 penalty”和“dylan choose the next song”)。

/*
Enter "quit" to end game
How many players?
7
Enter players' names:
john
kevin
mark
stacy
helen
jenna
dylan
helen, buy john a red bull or take 15 penalties
dylan chooses the next song

mark, let stacy look through your snap memories or take 8 penalties

helen has to say yes to mark for 5 minutes or take 8 penalties

Everyone switch drinks to the left
*/

我并不太关心代码的效率或者兰德()函数的典型缺陷,因为这是一个低风险的游戏,我主要关心的是让它一次打印出一行代码,但是,作为一个新的、公认的蹩脚的程序员,所有的建议都是受欢迎的。

sxpgvts3

sxpgvts31#

第一次迭代不会等待cin.ignore()(顺便说一句,这不是等待按下ENTER键的好方法),因为在读入最后一个球员的名字后,输入缓冲区中仍然存在一个换行符。
尝试使用std::getline()代替operator>>来读取每个玩家的名字,它会自动为你丢弃最后的换行符。
Why does std::getline() skip input after a formatted extraction?
此外,string players[numPlayers];不是标准C++:
Why aren't variable-length arrays part of the C++ standard?
请改用std::vector

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