我是GraphQL的新手,所以我看了看我的 Postman 请求。这是原始的 Postman 请求。
Request Headers
Content-Type: application/json
User-Agent: PostmanRuntime/7.29.2
Accept: */*
Cache-Control: no-cache
Postman-Token: e3239924-6e8a-48b9-bc03-3216ea6da544
Host: localhost:4000
Accept-Encoding: gzip, deflate, br
Connection: keep-alive
Content-Length: 94
Request Body
query: "query {
getTodo(todoId:3) {
id
text
done
}
}"
我尝试了以下方法
var url = "http://localhost:4000/query"
func TestGetTodoByID(t *testing.T) {
jsonData := `query {
getTodo(todoId:3) {
id
text
done
}
}`
fmt.Println(jsonData)
request, err := http.NewRequest("POST", url, bytes.NewBuffer([]byte(jsonData)))
request.Header.Set("Content-Type", "application/json")
request.Header.Set("Content-Length", fmt.Sprint(len(jsonData)))
client := &http.Client{Timeout: time.Second * 10}
response, err := client.Do(request)
defer response.Body.Close()
if err != nil {
fmt.Printf("The HTTP request failed with error %s\n", err)
}
data, err := io.ReadAll(response.Body)
if err != nil {
fmt.Printf("Error reading response with error %s\n", err)
}
responseBody := string(data)
if status := response.StatusCode; status != http.StatusOK {
t.Errorf("handler returned wrong status code: got %v want %v",
status, http.StatusOK)
}
expected := `{
"data": {
"getTodo": {
"id": 3,
"text": "qwert333 hello",
"done": true
}
}
}`
if responseBody != expected {
t.Errorf("handler returned unexpected body: got %v want %v",
responseBody, expected)
}
}
然后我得到了以下错误:
api_test.go:41: handler returned wrong status code: got 400 want 200
api_test.go:54: handler returned unexpected body: got {"errors":[{"message":"json request body could not be decoded: invalid character 'q' looking for beginning of value body:query {\n getTodo(todoId:3) {\n id\n text\n done\n }\n}"}],"data":null} want {
然后我也尝试了我在 Postman 控制台中找到的东西
jsonData := `"query":"query {
getTodo(todoId:3) {
id
text
done
}
}"`
这给了我一个稍微不同的错误
api_test.go:41: handler returned wrong status code: got 400 want 200
api_test.go:54: handler returned unexpected body: got {"errors":[{"message":"json request body could not be decoded: json: cannot unmarshal string into Go value of type graphql.RawParams body:\"query\":\"query {\n getTodo(todoId:3) {\n id\n text\n done\n }\n}\""}],"data":null} want {
有什么想法吗?
1条答案
按热度按时间2ul0zpep1#
标准的GraphQL JSON格式实际上是一个JSON对象,在Go语言环境中,最简单的创建方法是为
encoding/json
包添加一个结构注解(您可以寻找一个预先定义了该结构的专用GraphQL客户端包)。例如,您可以为该结构的最小形式创建一个结构
然后创建该结构的示例并将其序列化
您可能会发现,将响应数据
json.Unmarshal()
到具有标准格式的结构中同样有用,Data
字段与查询的形状匹配。