python TypeError:对象函数不能用于await表达式

a2mppw5e  于 2022-12-17  发布在  Python
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我创建了一个异步函数add_reaction_tasks,它将特定的函数Map到字典键,这个函数将字典返回到一个变量tasks,这个变量位于事件on_raw_reaction_add中。
第一个问题是tasks = await add_reaction_tasks()会引发以下错误:line 343, in _run_event await coro(*args, **kwargs) .
第二个错误是,当我尝试使用键which_trigger和参数payload访问由tasks表示的字典时,出现以下错误:
'1' : await add_rules_messages_tasks, TypeError: object function can't be used in 'await' expression .
我已经确保在可能的情况下使用await。除此之外,我不确定我还必须做些什么才能使这段代码工作。
代码片段:

1)add_reaction_tasks中使用的函数

def display_messages_error(payload = discord.RawReactionActionEvent):
                            ...
async def add_rules_messages_tasks(payload = discord.RawReactionActionEvent):
                            ...
async def add_years_messages_tasks(payload = discord.RawReactionActionEvent):
                            ...
async def add_programming_languages(payload = discord.RawReactionActionEvent):
                            ...

2)添加React任务函数

async def add_reaction_tasks():
    add_tasks = {
                    '0' : display_messages_error,
                    '1' : await add_rules_messages_tasks,
                    '2' : await add_years_messages_tasks,
                    '3' : await add_programming_languages
                }
    
    return add_tasks

3)原始React添加事件时

@bot.event
@commands.bot_has_permissions(manage_roles = True)
async def on_raw_reaction_add(payload : discord.RawReactionActionEvent):
    role  = None
    guild = None
    # if the guild is server_name
    if payload.guild_id == server_id:
        guild = find(lambda g : g.id == server_id, bot.guilds)
    
    member = get(guild.members, id = payload.user_id)

    if not guild: return
    if not member: return

    which_trigger = 0 # 0 stands for invalid message id (should trigger display_message_error function)
    try:
        which_trigger = str(all_role_reaction_ids[str(payload.message_id)]) # <= looks weird, but works
        #print(f'\nwhich_trigger = {which_trigger}\n')
    except KeyError as err:
        print(f'KeyError: {err}')
        print('Invalid role-reaction message id')
        return

    tasks = await add_reaction_tasks()  # <= first error
    
    await tasks[which_trigger](payload) # <= second error

    return
vfh0ocws

vfh0ocws1#

即使字典中的最后三个函数是异步的,删除它们前面的await也会使它们正常工作,不会引发错误。
但是,由于在它们之前没有使用await关键字,它们如何异步运行呢?

工作代码

async def add_reaction_tasks():
    add_tasks = {
                    '0' : display_messages_error,
                    '1' : add_rules_messages_tasks,
                    '2' : add_years_messages_tasks,
                    '3' : add_programming_languages
                }
    
    return add_tasks

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