我正在写一个脚本发送代理文件从一个目录到电报通道。在一些好人的帮助下,我几乎能够完成它
from telegram import Bot, InputMediaDocument
BOT_TOKEN = "xxx"
CHAT_ID = xxx
def main():
bot = Bot(BOT_TOKEN)
file_paths = (
"proxy/proxies/http.txt",
"proxy/proxies/socks4.txt",
"proxy/proxies/socks5.txt"
)
path_http = "proxy/proxies/http.txt"
with open(path_http,'rb') as file_http:
http_count = len(file_http.readlines())
file_http.close()
path_socks4 = 'proxy/proxies/socks4.txt'
with open(path_socks4,'rb') as file_socks4:
socks4_count = len(file_socks4.readlines())
file_socks4.close()
path_socks5 = 'proxy/proxies/socks5.txt'
with open(path_socks5,'rb') as file_socks5:
socks5_count = len(file_socks5.readlines())
file_socks5.close()
text = f"Total HTTPs:{http_count}\nTotal SOCKS4:{socks4_count}\nTotal SOCKS5:{socks5_count}"
media_group = list()
for f in file_paths:
with open(f, "rb") as fin:
caption = text if f == "proxy/proxies/http.txt" else ''
fin.seek(0)
media_group.append(InputMediaDocument(fin, caption=caption))
bot.send_media_group(CHAT_ID, media=media_group)
if __name__ == "__main__":
main()
发生的问题
media_group = list()
^
IndentationError: unindent does not match any outer indentation level
我尝试的是将这3个代理文件与标题一起发送到第一个代理文件
3条答案
按热度按时间xnifntxz1#
您的程式码有几个问题:
1.缺乏适当的压痕
1.括号闭合不当
你在
path_http = 'proxy/proxies/http.txt'
行得到的SyntaxError
是因为你没有把上一行(你初始化变量file_paths
的那一行)的括号括起来。我也预见到当你试图用
open
函数打开文件时会遇到问题,你可以在这里找到一些例子:https://www.programiz.com/python-programming/file-operationdz6r00yl2#
无效的语法错误可能是因为)在结尾不存在。
尝试添加(““)
caption = text if f == "proxy/proxies/http.txt" else ''
,因为它是字符串。vuktfyat3#
在一些好人的帮助下,我使它工作,如果有任何简单的版本免费分享