我正在使用node-rtsp-stream包来运行rtsp流,我如何在mvc结构中实现和回调它//Controller
var RTSP = require('./models/rtsp.js');
var startRTSP = function startRTSP(queryData) {
console.log("startRTSP enterred******************")
console.log("queryData : "+JSON.stringify(queryData))
stream = new Stream({
name: 'name',
streamUrl: 'rtsp://184.72.239.149/vod/mp4:BigBuckBunny_175k.mov',
wsPort: 9999
});
};
//型号
router.get('/', function(req,res){
RTSP.startRTSP(req.body);
res.send("SUCCESS")
})
//查看次数
$.ajax({
url:'/',
type:'POST',
cache:false,
success:function(data){
console.log("RTSP Result : "+JSON.stringify(data)
var canvas = document.getElementById('rtspvt');
var ws = new WebSocket("ws://localhost:9999")
var player = new jsmpeg(ws, {canvas:canvas, autoplay:true,audio:false,loop: true});
}
});
1条答案
按热度按时间cuxqih211#
安装ffmpeg全局在你的系统第一.
并导入ffmpeg npm包
let ffmpeg = require('ffmpeg');
现在尝试流式传输