如何在Selenium中模拟触摸屏?

o75abkj4  于 2022-12-23  发布在  其他
关注(0)|答案(2)|浏览(262)

我试图创建一个机器人,这个机器人必须点击一些元素,不承认鼠标点击,但承认触摸,我在网上搜索了一下,我发现了一种方法来模拟触摸事件。

from selenium import webdriver
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.touch_actions import TouchActions

user_agent = "Mozilla/5.0 (iPhone; U; CPU iPhone OS 3_0 like Mac OS X; en-us) AppleWebKit/528.18 (KHTML, like Gecko) Version/4.0 Mobile/7A341 Safari/528.16"
profile = webdriver.FirefoxProfile()
profile.set_preference("general.useragent.override", user_agent)
driver = webdriver.Firefox(profile)
driver.set_window_size(400, 800)

WebDriverWait(driver, 10).until(lambda d: d.find_element_by_css_selector(".qJfNm").is_displayed())
element = driver.find_element_by_css_selector(".qJfNm")
touchactions = TouchActions(driver)
touchactions.tap(element)

未出现错误,但不起作用,屏幕上无任何变化。根据文档https://seleniumhq.github.io/selenium/docs/api/java/org/openqa/selenium/interactions/touch/TouchActions.html
tap方法模拟mouse clicks,而不是touchscreen events,所以我想知道是否有一种方法可以在selenium上模拟touchscreen events,或者这是正确的方法,但我做错了。
我也试过写touchactions.tap(element).perform()而不是touchactions.tap(element)

from selenium import webdriver
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.touch_actions import TouchActions

user_agent = "Mozilla/5.0 (iPhone; U; CPU iPhone OS 3_0 like Mac OS X; en-us) AppleWebKit/528.18 (KHTML, like Gecko) Version/4.0 Mobile/7A341 Safari/528.16"
profile = webdriver.FirefoxProfile()
profile.set_preference("general.useragent.override", user_agent)
driver = webdriver.Firefox(profile)
driver.set_window_size(400, 800)

WebDriverWait(driver, 10).until(lambda d: d.find_element_by_css_selector(".qJfNm").is_displayed())
element = driver.find_element_by_css_selector(".qJfNm")
touchactions = TouchActions(driver)
touchactions.tap(element).perform()

但它引发了这个错误

Traceback (most recent call last):
  File "C:/Users/mcara/OneDrive/Desktop/instagram bot mobile/instagram_bot_mobile.py", line 57, in <module>
    touchactions.tap(element).perform()
  File "C:\Users\mcara\PycharmProjects\1\venv\lib\site-packages\selenium\webdriver\common\touch_actions.py", line 47, in perform
    action()
  File "C:\Users\mcara\PycharmProjects\1\venv\lib\site-packages\selenium\webdriver\common\touch_actions.py", line 57, in <lambda>
    Command.SINGLE_TAP, {'element': on_element.id}))
  File "C:\Users\mcara\PycharmProjects\1\venv\lib\site-packages\selenium\webdriver\remote\webdriver.py", line 321, in execute
    self.error_handler.check_response(response)
  File "C:\Users\mcara\PycharmProjects\1\venv\lib\site-packages\selenium\webdriver\remote\errorhandler.py", line 242, in check_response
    raise exception_class(message, screen, stacktrace)
selenium.common.exceptions.WebDriverException: Message: POST /session/71d75201-9012-46a1-9c6e-1c720dd332ce/touch/click did not match a known command

却不明白为什么。
我使用的是gekodriverpython 3windows 10

dluptydi

dluptydi1#

有趣的问题!也许点击在这种情况下是不够的,相反,我们需要使用double_tab旁边的chrome选项:)

from selenium import webdriver
from selenium.webdriver.chrome.options import Options

mobile_emulation = { "deviceName": "Nexus 6" }

chrome_options = Options()
chrome_options.add_experimental_option("mobileEmulation", mobile_emulation)

driver = webdriver.Chrome(chrome_options = chrome_options)
    WebDriverWait(driver, 10).until(lambda d: d.find_element_by_css_selector(".qJfNm").is_displayed())
    element = driver.find_element_by_css_selector(".qJfNm")
    touchactions = TouchActions(driver)
    touchactions.double_tab(element)
xriantvc

xriantvc2#

您也可以尝试:

from selenium.webdriver.common.actions import interaction
from selenium.webdriver.common.actions.action_builder import ActionBuilder

actions = ActionChains(driver)

# override as 'touch' pointer action
actions.w3c_actions = ActionBuilder(driver, mouse=PointerInput(interaction.POINTER_TOUCH, "touch"))
actions.w3c_actions.pointer_action.move_to_location(start_x, start_y)
actions.w3c_actions.pointer_action.pointer_down()
actions.w3c_actions.pointer_action.pause(2)
actions.w3c_actions.pointer_action.move_to_location(end_x, end_y)
actions.w3c_actions.pointer_action.release()
actions.perform()

发现于:appium-python-客户端

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