typescript 高阶函数的方法重载

pdtvr36n 于 2022-12-24 发布在 TypeScript

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目标是使用方法重载来构建开发人员友好的SDK。serviceType参数工作正常，但onMessage参数不工作。TypeScript是否不支持此功能？如果是，是否有解决方法？

type SwitchMessage = {
  propA: string;
};

type OutletMessage = {
  propB: string;
};

type ServiceType = "Switch" | "Outlet";
type ServiceMessage = SwitchMessage | OutletMessage;

class Client {
  subscribe(serviceType: "Switch", onMessage: (msg: SwitchMessage) => void);
  subscribe(serviceType: "Outlet", onMessage: (msg: OutletMessage) => void);
  subscribe(serviceType: ServiceType, onMessage: (msg: ServiceMessage) => void) {
    console.log("Hello")
  }
}

来自编译的消息：

This overload signature is not compatible with its implementation signature.

typescript

来源：https://stackoverflow.com/questions/74877641/method-overloading-of-higher-order-function

1条答案

按热度按时间

pkwftd7m1#

|处理函数参数的方式与您想象的 * 相反 *
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type SwitchMessage = {
  propA: string;
};

type OutletMessage = {
  propB: string;
};

type ServiceType = "Switch" | "Outlet";
type ServiceMessage = SwitchMessage | OutletMessage;

class Client {
  subscribe(serviceType: "Switch", onMessage: (msg: SwitchMessage) => void): void;
  subscribe(serviceType: "Outlet", onMessage: (msg: OutletMessage) => void): void;
  subscribe(serviceType: ServiceType, onMessage: (msg: SwitchMessage & OutletMessage) => void) {
    console.log("Hello")
  }
  
  subscribe2(serviceType: "Switch", onMessage: (msg: SwitchMessage) => void): void;
  subscribe2(serviceType: "Outlet", onMessage: (msg: OutletMessage) => void): void;
  subscribe2(serviceType: ServiceType, onMessage: ((msg: SwitchMessage) => void) | ((msg: OutletMessage) => void)) {
    console.log("Hello")
  }
}

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typescript 高阶函数的方法重载

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