javascript 如何获取socket.io客户端

iaqfqrcu  于 2022-12-25  发布在  Java
关注(0)|答案(1)|浏览(167)

我想构建socket.io服务器,但在设置客户端时出现错误(在客户端)Failed to load resource:http://localhost:3000/socket.io/?EIO=4&transport=polling&t=OK-egu3 the server responded with a status of 404 (Not Found)
验证码:

const express = require('express');
const app = express();
const http = require('http').createServer(app);
const io = require('socket.io')(http, {cors: {origin: "*"}});
const path = require('path');

app.set('view engine', 'ejs');

app.use(express.json({extended: true, limit: '1mb'}));

io.on('connection', (socket) => {
 console.log("new connection " + socket);
});

app.get("/", (req, res, next) => {
 res.render('index'/*, { ioS : io }*/);
});

console.log("Ready");

app.listen(3000);

index.ejs:

<!DOCTYPE html>
<html lang="en">
<head>
    <meta charset="UTF-8">
    <meta http-equiv="X-UA-Compatible" content="IE=edge">
    <meta name="viewport" content="width=device-width, initial-scale=1.0">
    <title>Document</title>
</head>
<body>
    <h1>socket Respons</h1>
</body>
<script src="https://cdn.socket.io/4.5.4/socket.io.min.js" integrity="sha384-/KNQL8Nu5gCHLqwqfQjA689Hhoqgi2S84SNUxC3roTe4EhJ9AfLkp8QiQcU8AMzI" crossorigin="anonymous"></script>
<script>
    //const io = ;
    const socket = io();
    console.log(socket);
</script>
</html>

我已经安装了以下库:
socket.io . io-客户端表达ejs

snvhrwxg

snvhrwxg1#

您没有正确初始化客户端,您的服务器位于localhost:3000,但客户端不知道这一点,因为您没有告诉它在哪里查找。
查看socketio文档,您需要传递服务器套接字端点的URL:

const URL = "http://localhost:3000";
const socket = io(URL, { autoConnect: false });

值得一提的是,错误消息指出:这不是一个冗长的错误消息,但却是一个有价值的调试信号。

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