Python：如何移除(替换为“”)Python字符串中的撇号和逗号组合

wrrgggsh 于 2022-12-27 发布在 Python

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我有一个像这样的字符串，前面附加了一些奇怪的字符（整个字符串）：

# Edited to make more clear. It is essentially this:

x = """
INFO     2022-12-27 16:56:25.843 request id: app - xxxxxx
', "INFO     2022-12-27 16:56:26.407 request id: app - xxxxxxx
", 'INFO     2022-12-27 16:56:26.407 request id: app - xxxxxx
INFO     2022-12-27 16:56:26.497 request id: app - xxxxxxxx
"""

# So need to remove the comma and apostrophes in the 2nd and 3rd line of string object x

我想删除第2行和第3行中的', "和', "，但由于撇号组合导致string literal is unterminated错误，因此很难替换或正则化它。

python-3.x

来源：https://stackoverflow.com/questions/74927056/python-how-to-remove-replace-with-combinations-of-apostrophes-and-commas-i

3条答案

按热度按时间

sdnqo3pr1#

假设每一行日志总是以INFO或DEBUG这样的关键字开头，我们可以在多行模式下对文本进行正则表达式替换：

logs = """INFO     2022-12-27 16:56:25.843 request id: app - xxxxxx
', \"INFO     2022-12-27 16:56:26.407 request id: app - xxxxxxx
\", 'INFO     2022-12-27 16:56:26.407 request id: app - xxxxxx
INFO     2022-12-27 16:56:26.497 request id: app - xxxxxxxx"""

output = re.sub(r'^[^A-Z]+', '', logs, flags=re.M)
print(output)

这将打印：

INFO     2022-12-27 16:56:25.843 request id: app - xxxxxx
INFO     2022-12-27 16:56:26.407 request id: app - xxxxxxx
INFO     2022-12-27 16:56:26.407 request id: app - xxxxxx
INFO     2022-12-27 16:56:26.497 request id: app - xxxxxxxx

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j2datikz2#

string_test = f"""INFO     2022-12-27 16:56:25.843 request id: app - xxxxxx
', "INFO     2022-12-27 16:56:26.407 request id: app - xxxxxxx
", 'INFO     2022-12-27 16:56:26.407 request id: app - xxxxxx
INFO     2022-12-27 16:56:26.497 request id: app - xxxxxxxx"""

string_test = string_test.replace(f"'", "")
print(string_test)

工作原理：将every '替换为nothing，将其删除。
希望这能帮上忙。

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pu3pd22g3#

假设您真正想要做的是删除任何行中"INFO"之前的任何内容，则：

mystring = """INFO     2022-12-27 16:56:25.843 request id: app - xxxxxx
', "INFO     2022-12-27 16:56:26.407 request id: app - xxxxxxx
", 'INFO     2022-12-27 16:56:26.407 request id: app - xxxxxx
INFO     2022-12-27 16:56:26.497 request id: app - xxxxxxxx"""

newstring = []

for line in mystring.splitlines():
    if (i := line.find('INFO')) >= 0:
        line = line[i:]
    newstring.append(line)

print('\n'.join(newstring))

- 输出：**

INFO     2022-12-27 16:56:25.843 request id: app - xxxxxx
INFO     2022-12-27 16:56:26.407 request id: app - xxxxxxx
INFO     2022-12-27 16:56:26.407 request id: app - xxxxxx
INFO     2022-12-27 16:56:26.497 request id: app - xxxxxxxx

赞(0）回复(0）举报 2022-12-27

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Python：如何移除(替换为“”)Python字符串中的撇号和逗号组合

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