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How to modify an array's values by a foreach loop?（2个答案）
昨天关闭。
Array1
(
[0] => Array
(
[date] => 2022-12-01
[result] => 0
)
[1] => Array
(
[date] => 2022-12-02
[result] => 0
)
[2] => Array
(
[date] => 2022-12-03
[result] => 0
)
.
.
.
.
[31] => Array
(
[date] => 2022-12-31
[result] => 0
)
)
Array2
(
[0] => Array
(
[date] => 2022-12-01
[result] => 45
)
[1] => Array
(
[date] => 2022-12-03
[result] => 15
)
.
.
.
.
[25] => Array
(
[date] => 2022-12-31
[result] => 25
)
)
Array3
(
[0] => Array
(
[date] => 2022-12-01
[result] => 45
)
[1] => Array
(
[date] => 2022-12-02
[result] => 0
)
[2] => Array
(
[date] => 2022-12-03
[result] => 15
)
.
.
.
.
[31] => Array
(
[date] => 2022-12-31
[result] => 25
)
)我想把Array1和Array2合并成Array3。数组1包含所有空值月份的日期，而Array2只包含有值的日期。所以，我想循环两个数组，如果日期在Array2中，则使用Array2的值，否则使用Array1的0值。我尝试使用for每个循环，但Array!中的结果没有做任何更改。下面是我的代码：
foreach($Array1 as $arr1){
foreach($Array2 as $arr2){
if($arr1['date'] == $arr2['date']){
$arr1['date'] = $arr2['date'];
$arr1['result'] = $arr2['result'];
}
}
}
1条答案
按热度按时间z9smfwbn1#
你需要将
$arr1作为一个引用变量，这样赋值给它就可以修改数组，否则你修改的是数组的一个副本，当循环结束时，所做的修改就会丢失。也不需要
$arr1['date'] = $arr2['date'];，因为if条件意味着它们相同。