java 调用错误的客户端如下所示:org.xml.sax.SAXException:SimpleDeserializer遇到了不应有的子元素

k4emjkb1  于 2023-01-01  发布在  Java
关注(0)|答案(1)|浏览(965)

谁能帮帮我,我快要崩溃了,所以谢谢你客户端调用错误如下,错误:客户端调用错误如下,error:

- Exception:
org.xml.sax.SAXException: SimpleDeserializer encountered a child element, which is NOT expected, in something it was trying to deserialize.
    at org.apache.axis.encoding.ser.SimpleDeserializer.onStartChild(SimpleDeserializer.java:145)
    at org.apache.axis.encoding.DeserializationContext.startElement(DeserializationContext.java:1035)
    at org.apache.axis.message.SAX2EventRecorder.replay(SAX2EventRecorder.java:165)
    at org.apache.axis.message.MessageElement.publishToHandler(MessageElement.java:1141)
    at org.apache.axis.message.RPCElement.deserialize(RPCElement.java:236)
    at org.apache.axis.message.RPCElement.getParams(RPCElement.java:384)
    at org.apache.axis.client.Call.invoke(Call.java:2467)
    at org.apache.axis.client.Call.invoke(Call.java:2366)
    at org.apache.axis.client.Call.invoke(Call.java:1812)
    at com.hxc.soap.HxcNewsServiceSoap12BindingStub.find(HxcNewsServiceSoap12BindingStub.java:254)
    at com.hxc.soap.Test.main(Test.java:11)
AxisFault
 faultCode: {http://schemas.xmlsoap.org/soap/envelope/}Server.userException
 faultSubcode: 
 faultString: org.xml.sax.SAXException: SimpleDeserializer encountered a child element, which is NOT expected, in something it was trying to deserialize.
 faultActor: 
 faultNode: 
 faultDetail: 
    {http://xml.apache.org/axis/}stackTrace:org.xml.sax.SAXException: SimpleDeserializer encountered a child element, which is NOT expected, in something it was trying to deserialize.
    at org.apache.axis.encoding.ser.SimpleDeserializer.onStartChild(SimpleDeserializer.java:145)
    at org.apache.axis.encoding.DeserializationContext.startElement(DeserializationContext.java:1035)
    at org.apache.axis.message.SAX2EventRecorder.replay(SAX2EventRecorder.java:165)
    at org.apache.axis.message.MessageElement.publishToHandler(MessageElement.java:1141)
    at org.apache.axis.message.RPCElement.deserialize(RPCElement.java:236)
    at org.apache.axis.message.RPCElement.getParams(RPCElement.java:384)
    at org.apache.axis.client.Call.invoke(Call.java:2467)
    at org.apache.axis.client.Call.invoke(Call.java:2366)
    at org.apache.axis.client.Call.invoke(Call.java:1812)
    at com.hxc.soap.HxcNewsServiceSoap12BindingStub.find(HxcNewsServiceSoap12BindingStub.java:254)
    at com.hxc.soap.Test.main(Test.java:11)

    {http://xml.apache.org/axis/}hostname:geduo_pc

org.xml.sax.SAXException: SimpleDeserializer encountered a child element, which is NOT expected, in something it was trying to deserialize.
    at org.apache.axis.AxisFault.makeFault(AxisFault.java:101)
    at org.apache.axis.client.Call.invoke(Call.java:2470)
    at org.apache.axis.client.Call.invoke(Call.java:2366)
    at org.apache.axis.client.Call.invoke(Call.java:1812)
    at com.hxc.soap.HxcNewsServiceSoap12BindingStub.find(HxcNewsServiceSoap12BindingStub.java:254)
    at com.hxc.soap.Test.main(Test.java:11)
Caused by: org.xml.sax.SAXException: SimpleDeserializer encountered a child element, which is NOT expected, in something it was trying to deserialize.
    at org.apache.axis.encoding.ser.SimpleDeserializer.onStartChild(SimpleDeserializer.java:145)
    at org.apache.axis.encoding.DeserializationContext.startElement(DeserializationContext.java:1035)
    at org.apache.axis.message.SAX2EventRecorder.replay(SAX2EventRecorder.java:165)
    at org.apache.axis.message.MessageElement.publishToHandler(MessageElement.java:1141)
    at org.apache.axis.message.RPCElement.deserialize(RPCElement.java:236)
    at org.apache.axis.message.RPCElement.getParams(RPCElement.java:384)
    at org.apache.axis.client.Call.invoke(Call.java:2467)
    ... 4 more

服务器代码:(axis 2+休眠+Spring)

public class HxcNewsService implements IHxcNewsService {    
    private IDao dao;   
    public void setDao(IDao dao) {
        this.dao = dao;
    }
    public HxcNews find(int id){
        return (HxcNews) dao.find("com.ews.bean.HxcNews",id);
    }
}

public class Dao<T> extends HibernateDaoSupport implements IDao<T> {

    public T find(String str,int id) {

        try {
            T t = (T) getHibernateTemplate().get(str, id);
            return t;
        } catch (RuntimeException re) {         
            throw re;
        }

    }

}

客户代码:

public class Test {
    public static void main(String[] args) {
        try {
            HxcNewsServicePortType hxcNewsServicePortType = new HxcNewsServiceLocator().getHxcNewsServiceHttpSoap12Endpoint();
            HxcNews news = hxcNewsServicePortType.find(1);
            System.out.println(news.getTitle());                    
        } catch (ServiceException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        } catch (RemoteException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }

    }
}
3zwjbxry

3zwjbxry1#

我认为这个错误是由于HcxNewsService类的find()方法返回的xml输出造成的。一些XML成功返回,但它的格式不足以反序列化(* 重新构造一个对象 *)。
正如堆栈跟踪中提到的......“encountered a child element, which is NOT expected, in something it was trying to deserialize“(SAXParser不理解XML意味着xml格式不正确)。
可能的调试选项是尝试直接从DAO获取XML绑定对象...记录它...

public class Dao<T> extends HibernateDaoSupport implements IDao<T> {

    public T find(String str,int id) {

        try {
            T t = (T) getHibernateTemplate().get(str, id);
            System.out.println.t.toString()); // OR...
            LOGGER.info(t.toString());
            return t;
        } cach (RuntimeException re) {         
            throw re;
        }

    }
}

如果这失败了,请对服务器中的调用代码执行相同的方法...

public class HxcNewsService implements IHxcNewsService {    
    private IDao dao;   
    public void setDao(IDao dao) {
        this.dao = dao;
    }
    public HxcNews find(int id){
        // before returning, see what is database returning...
        LOGGER.log(dao.find("com.ews.bean.HxcNews",id));
        return (HxcNews) dao.find("com.ews.bean.HxcNews",id);
    }
}

让我们知道你最后是怎么解决的。

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