I want to get the 10th value ie. value ofPrice/Bookof the 10th in an .
我试过以下方法，但没有效果。每次我得到第一个元素时，都不是第10个元素。
block = driver.find_element(by=By.XPATH, value="//ul[contains(@class, 'small-block-grid-3 large-block-grid-4 sal-component-band-grid')]/li[10]")
value = block.find_element(by=By.XPATH, value="//div[contains(@class, 'dp-value')]").textblock = driver.find_element(by=By.XPATH, value="//ul[contains(@class, 'small-block-grid-3 large-block-grid-4 sal-component-band-grid')]/li[position()=10]")
value = block.find_element(by=By.XPATH, value="//div[contains(@class, 'dp-value')]").textblock = driver.find_element(by=By.XPATH, value="//ul[contains(@class, 'small-block-grid-3 large-block-grid-4 sal-component-band-grid')]").find_element(by=By.XPATH, value="//li[10][contains(@class, 'snap-panel')]")
value = block.find_element(by=By.XPATH, value="//div[contains(@class, 'dp-value')]").textblock = driver.find_element(by=By.XPATH, value="//ul[contains(@class, 'small-block-grid-3 large-block-grid-4 sal-component-band-grid')]").find_element(by=By.XPATH, value="//li[position()=10][contains(@class, 'snap-panel')]")
value = block.find_element(by=By.XPATH, value="//div[contains(@class, 'dp-value')]").textblock = driver.find_element(by=By.XPATH, value="//ul[contains(@class, 'small-block-grid-3 large-block-grid-4 sal-component-band-grid')]").find_elements(by=By.XPATH, value="//li[contains(@class, 'snap-panel')]")
for item in block:
name = item.find_element(by=By.XPATH, value="//div[contains(@class, 'dp-name')]").text
if 'Price/Book' in name:
value = item.find_element(by=By.XPATH, value="//div[contains(@class, 'dp-value')]").text我怎样才能得到第10个元素？
2条答案
按热度按时间clj7thdc1#
您可以使用以下XPATH获取第10个
<li>的dp-value：w6lpcovy2#
要获得第n个元素，有一个CSS选择器！
使用
nth-of-tyeCSS选择器：例如，在您的情况下：
这将查找第10个
<li>标记。您还可以将其与其他CSS选择器组合使用以缩小搜索范围，例如，您的CSS选择器可以是：
.用于选择CSS类。另请参见
CSS selectors (w3schools)