ios 无法使用LinkedIn的OAuth初学者工具包共享

new9mtju  于 2023-01-06  发布在  iOS
关注(0)|答案(1)|浏览(101)

我使用OAuthStarter Kit访问LinkedIn API。我成功获取权限的访问令牌。

rw_ns
r_基本配置文件
r_完整配置文件

这是可能的个人资料的详细信息,以及只分享意见,而共享的URL或图像或描述等...我使用以下代码:

-(void)postUpdate
 {
   NSURL *url = [NSURL URLWithString:@"http://api.linkedin.com/v1/people/~/shares"];
   OAMutableURLRequest *request =
   [[OAMutableURLRequest alloc] initWithURL:url
                            consumer:[self getConsumer]
                               token:self.accesstoken
                            callback:nil
                   signatureProvider:nil];

   NSDictionary *update = [[NSDictionary alloc] initWithObjectsAndKeys:
                    
                    [[NSDictionary alloc]
                     initWithObjectsAndKeys:
                     @"anyone",@"code",nil], @"visibility",
                    @"title goes here",@"title",
                    @"comment goes here", @"comment",
                    @"description goes here",@"description",
                     @"www.google.com",@"submitted-url",
                    @"http://economy.blog.ocregister.com/files/2009/01/linkedin-logo.jpg",@"submitted-image-url",
                    nil];
   [request setValue:@"json" forHTTPHeaderField:@"x-li-format"];
   [request setValue:@"application/json" forHTTPHeaderField:@"Content-Type"];

   NSString *updateString = [update JSONString];
   [request setHTTPBodyWithString:updateString];
    [request setHTTPMethod:@"POST"];

   OADataFetcher *fetcher = [[OADataFetcher alloc] init];
   [fetcher fetchDataWithRequest:request
                 delegate:self
        didFinishSelector:@selector(postUpdateApiCallResult:didFinish:)
          didFailSelector:@selector(postUpdateApiCallResult:didFail:)];

  }

但我得到了如下响应错误:

2012-10-09 18:27:29.906 SocialConnectTest[9460:19a03] data {
 "errorCode": 0,
 "message": "Invalid xml {Expected elements 'post-network-update@http://api.linkedin.com/v1 id@http://api.linkedin.com/v1 visibility@http://api.linkedin.com/v1 comment@http://api.linkedin.com/v1 attribution@http://api.linkedin.com/v1 content@http://api.linkedin.com/v1 private-message@http://api.linkedin.com/v1 share-target-reach@http://api.linkedin.com/v1' instead of 'submitted-url@http://api.linkedin.com/v1' here in element share@http://api.linkedin.com/v1}",
 "requestId": "W2G7WJDHOJ",
 "status": 400,
 "timestamp": 1349787449685
}

我不知道问题出在哪里。我该怎么着手解决呢?

pjngdqdw

pjngdqdw1#

我修好了,问题出在后参数上
1.根据Linked in API的文档,* 如果我们在请求主体中使用JSON,则后置参数的键必须为驼峰式,而在xml中使用**"-"分隔的键名 *。
1.submittedUrl、subsubmittedImageUrl、描述、标题等共享参数必须是名为
content**的键的值。
所以我修改了代码如下。

-(void)postUpdateHERE
{
  NSURL *url = [NSURL URLWithString:@"http://api.linkedin.com/v1/people/~/shares"];
  OAMutableURLRequest *request =
  [[OAMutableURLRequest alloc] initWithURL:url
                            consumer:[self getConsumer]
                               token:self.accesstoken
                            callback:nil
                   signatureProvider:nil];

  NSDictionary *update = [[NSDictionary alloc] initWithObjectsAndKeys:

                    [[NSDictionary alloc]
                     initWithObjectsAndKeys:
                     @"anyone",@"code",nil], @"visibility",

                    @"comment goes here", @"comment",
                    [[NSDictionary alloc]
                     initWithObjectsAndKeys:
                    @"description goes here",@"description",
                    @"www.google.com",@"submittedUrl",
                      @"title goes here",@"title",
                    @"http://economy.blog.ocregister.com/files/2009/01/linkedin-logo.jpg",@"submittedImageUrl",nil],@"content",
                    nil];
  [request setValue:@"json" forHTTPHeaderField:@"x-li-format"];
  [request setValue:@"application/xml" forHTTPHeaderField:@"Content-Type"];
  NSString *updateString = [update JSONString];
  [request setHTTPBodyWithString:updateString];
  [request setHTTPMethod:@"POST"];
  OADataFetcher *fetcher = [[OADataFetcher alloc] init];
  [fetcher fetchDataWithRequest:request
                 delegate:self
        didFinishSelector:@selector(postUpdateApiCallResult:didFinish:)
          didFailSelector:@selector(postUpdateApiCallResult:didFail:)];

}

现在代码对我起作用了。

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