我使用OAuthStarter Kit访问LinkedIn API。我成功获取权限的访问令牌。
rw_ns
r_基本配置文件
r_完整配置文件
这是可能的个人资料的详细信息,以及只分享意见,而共享的URL或图像或描述等...我使用以下代码:
-(void)postUpdate
{
NSURL *url = [NSURL URLWithString:@"http://api.linkedin.com/v1/people/~/shares"];
OAMutableURLRequest *request =
[[OAMutableURLRequest alloc] initWithURL:url
consumer:[self getConsumer]
token:self.accesstoken
callback:nil
signatureProvider:nil];
NSDictionary *update = [[NSDictionary alloc] initWithObjectsAndKeys:
[[NSDictionary alloc]
initWithObjectsAndKeys:
@"anyone",@"code",nil], @"visibility",
@"title goes here",@"title",
@"comment goes here", @"comment",
@"description goes here",@"description",
@"www.google.com",@"submitted-url",
@"http://economy.blog.ocregister.com/files/2009/01/linkedin-logo.jpg",@"submitted-image-url",
nil];
[request setValue:@"json" forHTTPHeaderField:@"x-li-format"];
[request setValue:@"application/json" forHTTPHeaderField:@"Content-Type"];
NSString *updateString = [update JSONString];
[request setHTTPBodyWithString:updateString];
[request setHTTPMethod:@"POST"];
OADataFetcher *fetcher = [[OADataFetcher alloc] init];
[fetcher fetchDataWithRequest:request
delegate:self
didFinishSelector:@selector(postUpdateApiCallResult:didFinish:)
didFailSelector:@selector(postUpdateApiCallResult:didFail:)];
}
但我得到了如下响应错误:
2012-10-09 18:27:29.906 SocialConnectTest[9460:19a03] data {
"errorCode": 0,
"message": "Invalid xml {Expected elements 'post-network-update@http://api.linkedin.com/v1 id@http://api.linkedin.com/v1 visibility@http://api.linkedin.com/v1 comment@http://api.linkedin.com/v1 attribution@http://api.linkedin.com/v1 content@http://api.linkedin.com/v1 private-message@http://api.linkedin.com/v1 share-target-reach@http://api.linkedin.com/v1' instead of 'submitted-url@http://api.linkedin.com/v1' here in element share@http://api.linkedin.com/v1}",
"requestId": "W2G7WJDHOJ",
"status": 400,
"timestamp": 1349787449685
}
我不知道问题出在哪里。我该怎么着手解决呢?
1条答案
按热度按时间pjngdqdw1#
我修好了,问题出在后参数上
1.根据Linked in API的文档,* 如果我们在请求主体中使用JSON,则后置参数的键必须为驼峰式,而在xml中使用**"-"分隔的键名 *。
1.submittedUrl、subsubmittedImageUrl、描述、标题等共享参数必须是名为content**的键的值。
所以我修改了代码如下。
现在代码对我起作用了。