该程序是一个密码生成器，允许用户选择是否希望小写、大写、数字和特殊字符作为密码的一部分。每个相应的选择都存储在一个字符集数组中。
我已经成功地创建了这个程序，如果所有选项都为真，它就会按预期运行。这些选项被存储为来自confirm()的变量。然后我将所有这些变量存储在一个对象中，以方便引用。
不幸的是，当任何一个条件为假时，我都无法执行程序。我无法计算出程序仍然执行并忽略假条件的逻辑，只能从为真的变量中提供选项。我认为使用选项生成密码的逻辑是我出错的地方。除了使用多个if/else分支来评估每个可能的组合之外，我找不到一种干的方式来做这件事。

// Function to prompt user for password options
function getPasswordOptions() {
 
  var passwordLength;
  do {
    passwordLength = parseInt(prompt("How many characters would you like in your password (between 10 and 64)?"));
  } while (passwordLength < 10 || passwordLength > 64);

  // All the prompts for the type of password options that the user would like.
  var lowercase = confirm("Would you like lowercase characters in your password?");
  var uppercase = confirm("Would you like uppercase characters in your password?");
  var special = confirm("Would you like special characters in your password?");
  var numbers = confirm("Would you like numbers in your password?");

  var userPasswordOpts = {
    plength: passwordLength,
    opt1: lowercase,
    opt2: uppercase,
    opt3: special,
    opt4: numbers
  };

  return userPasswordOpts;
}

// Function for getting a random element from an array
function getRandom(arr) {
  return arr[Math.floor(Math.random() * arr.length)];
}

// Function to generate password with user input
function generatePassword() {
  var userPasswordChoice = getPasswordOptions();
  var passwordArr = [];

  if (Object.values(userPasswordChoice)) {
    for (var i = 0; i < userPasswordChoice.plength; i++) {

      var randomNum = Math.floor(Math.random() * 3) + 1;

      switch(randomNum) {
        case 1:
          passwordArr.push(getRandom(lowerCasedCharacters));
        break;
        case 2:
          passwordArr.push(getRandom(upperCasedCharacters));
        break;
        case 3:
          passwordArr.push(getRandom(specialCharacters));
        break;
        case 4:
          passwordArr.push(getRandom(numericCharacters));
        default:
          null;
      }
    }
  }
  return passwordArr.join('');
}