我使用API在应用程序中检索图书详细信息,有两种途径:一个包含表单和搜索结果,另一个包含每个搜索结果的完整详细信息。当前,详细信息页面上有一个链接,可将我带回到表单页面,但我希望保留表单页面的状态,并在单击链接时显示搜索结果,而不仅仅是表单。如何才能做到这一点?
你可以检查我下面的代码.
BookDetails.jsx
import { useParams } from "react-router-dom";
import fetchBookDetails from "../hooks/fetchBookDetails";
import { useQuery } from "@tanstack/react-query";
import { Link } from "react-router-dom";
import notFoundImage from "../assets/react.svg";
import Header from "./Header";
const BookDetails = () => {
const { id } = useParams();
const results = useQuery(["book", id], fetchBookDetails);
if (results.isLoading) {
return <div>Loading...</div>;
}
if (results.isError) {
return <div>Book with id {id} not found.</div>;
}
if (results.data) {
return (
<div>
<Header />
<Link to="/">
<button className="back">Back</button>
</Link>
<div className="book-details">
<img
src={
results.data.volumeInfo.imageLinks
? results.data.volumeInfo.imageLinks.thumbnail
: notFoundImage
}
alt={results.data.volumeInfo.title}
/>
<h1>{results.data.volumeInfo.title}</h1>
<p>{results.data.volumeInfo.authors}</p>
</div>
</div>
);
}
};
export default BookDetails;
SearchForm.jsx
const SearchForm = ({ onSubmit }) => {
const handleSubmit = (e) => {
e.preventDefault();
onSubmit(e.target.elements.book.value);
};
return (
<>
{" "}
<div>
<form onSubmit={handleSubmit}>
<label htmlFor="book">
Book Name:
<input type="text" name="book" />
</label>
<button type="submit">Submit</button>
</form>
</div>
</>
);
};
export default SearchForm;
Seachresult.jsx
import React from "react";
import { Link } from "react-router-dom";
import notFoundImage from "../assets/react.svg";
const SearchResults = ({ results }) => {
return results.isLoading ? (
<div>Loading...</div>
) : results.isError ? (
<div>{results.error.message}</div>
) : (
<div className="books">
{results.data.items.map((item, i) => {
return (
<Link to={`/book/${item.id}`} key={item.id}>
<div key={item.id} className="book border-2-red-500">
<p>{i + 1}</p>
<img
src={
item.volumeInfo.imageLinks
? item.volumeInfo.imageLinks.thumbnail
: notFoundImage
}
alt={item.volumeInfo.title}
/>
<h3>{item.volumeInfo.title}</h3>
<p>{item.volumeInfo.authors}</p>
</div>
</Link>
);
})}
</div>
);
};
export default SearchResults;
Home.jsx
import { useState } from "react";
import { useQuery } from "@tanstack/react-query";
import fetchBooks from "../hooks/fetchBooks";
import SearchResults from "./SearchResults";
import SearchForm from "./SearchForm";
import Header from "./Header";
const Home = () => {
const [book, setBook] = useState(null);
const results = useQuery(["search", book], fetchBooks);
return (
<main>
<Header />
<SearchForm onSubmit={setBook} />
<SearchResults results={results} />
</main>
);
};
export default Home;
最后是App.jsx
import "./App.css";
import { QueryClient, QueryClientProvider } from "@tanstack/react-query";
import Home from "./components/Home";
import { BrowserRouter, Routes, Route } from "react-router-dom";
import BookDetails from "./components/BookDetails";
const queryClient = new QueryClient({
defaultOptions: {
queries: {
staleTime: Infinity,
cacheTime: Infinity,
},
},
});
function App() {
return (
<BrowserRouter>
<QueryClientProvider client={queryClient}>
<Routes>
<Route path="/book/:id" element={<BookDetails />} />
<Route path="/" element={<Home />} />
</Routes>
</QueryClientProvider>
</BrowserRouter>
);
}
export default App;
1条答案
按热度按时间noj0wjuj1#
您可以使用React Context API,创建一个Context来 Package 您想要授予访问这些状态的权限的组件,然后您可以以“全局”方式管理状态,以便在来回切换时保持其完整性。
您可以查看以下示例: