我想解析特定类中的以下日志。
2019-11-14T04:24:04.072Z INFO MessagingObjectFactoryImpl-4-2 ExporterLastAckServiceImpl - - [nsx@6876 comp="nsx-manager" level="INFO" subcomp="manager"] Found exporter with elaId = Node#a3844284-e626-11e9-a87b-005056bcc0c6#AggSvc-L2-Bridging, returning lastAck = 16507
2019-11-14T04:23:08.362Z INFO ActivityEventRecovery-1 ActivityCacheManager - - [nsx@6876 comp="nsx-manager" level="INFO" subcomp="manager"] Handling activity 92d6a146-fa12-4889-a0ff-441087e047d0 completion event for 1
2019-11-14T04:23:08.362Z DEBUG ActivityEventRecovery-1 ActivityCacheManager - - [nsx@6876 comp="nsx-manager" level="INFO" subcomp="manager"] Handling activity 92d6a146-fa12-4889-a0ff-441087e047d0 completion event for 1
我试过了
(?<timestamp>\d\d\d\d-\d\d-\d\dT\d\d:\d\d:\d\d.\d\d\dZ)\s+(?<level>INFO|WARN|DEBUG|ERROR|FATAL|TRACE)\s+(?<text>.*?\s.*?)\-\s+\-\s\[(?<class>.*?)\]\s+(?<Message>.*? |\Z)
我得到了所有的东西,除了消息类。我应该怎么写消息类正则表达式?
下面是链接https://regex101.com/r/LJnVrS/86
1条答案
按热度按时间jv4diomz1#
.*?
将匹配尽可能少的字符,直到您到达一个空格。因为看起来匹配的字符都在一行的末尾结束,所以您可以继续匹配任何字符,直到您到达该行的末尾。删除s
标志,并用途:(no需要
\Z
)https://regex101.com/r/LJnVrS/87