return [text.count(string) for string in string_list]

下面是一个很长的方法：

from collections import defaultdict

string_list = ["red","blue","green"]
text = "This is a string about my favourite colours like red blue and green but blue is the best"

def count_occurrences(string_list, text):
    counts = defaultdict(int)
    for string in text.split():
        if string in string_list:
            counts[string] += 1
    return counts.values()

print(count_occurrences(string_list, text))

dict_values([1, 2, 1])

你可以使用count()函数来计算字符串中的子字符串。下面的代码可能会有所帮助

def get_count(slist,text):
    result=[]
    for string in slist:
        result.append(text.count(string))
    return result
    

string_list = ["red","blue","green"]
text = "This is a string about my favourite colours like red blue and green but blue is the best"

print(get_count(string_list,text))

输出

[1, 2, 1]