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我开始学习Rust,在Sushing中,我有hashmap3练习,编码如下
fn build_scores_table(results: String) -> HashMap<String, Team> {
// The name of the team is the key and its associated struct is the value.
let mut scores: HashMap<String, Team> = HashMap::new();
for r in results.lines() {
let v: Vec<&str> = r.split(',').collect();
let team_1_name = v[0].to_string();
let team_1_score: u8 = v[2].parse().unwrap();
let team_2_name = v[1].to_string();
let team_2_score: u8 = v[3].parse().unwrap();
let t1 = scores.entry(team_1_name.clone()).or_insert(Team {
name: team_1_name,
goals_scored: 0,
goals_conceded: 0,
});
t1.goals_scored += team_1_score;
t1.goals_conceded += team_2_score;
let t2 = scores.entry(team_2_name.clone()).or_insert(Team {
name: team_2_name,
goals_scored: 0,
goals_conceded: 0,
});
t2.goals_conceded += team_1_score;
t2.goals_scored += team_2_score;
// TODO: Populate the scores table with details extracted from the
// current line. Keep in mind that goals scored by team_1
// will be the number of goals conceded from team_2, and similarly
// goals scored by team_2 will be the number of goals conceded by
// team_1.
}
println!("{:?}", scores);
scores
}
但随后也找到了GitHub中其他铁 rust 开发和使用的答案
let t1 = scores.entry(team_1_name.clone()).or_insert(Team {
name: team_1_name,
goals_scored: 0,
goals_conceded: 0,
});
(*t1).goals_scored += team_1_score;
(*t1).goals_conceded += team_2_score;
let t2 = scores.entry(team_2_name.clone()).or_insert(Team {
name: team_2_name,
goals_scored: 0,
goals_conceded: 0,
});
(*t2).goals_conceded += team_1_score;
(*t2).goals_scored += team_2_score;
这两个实现都能工作,并且通过了练习测试,但是在这里使用(*t1)
有什么意义呢?抱歉问了这个愚蠢的问题,感谢您的帮助。
1条答案
按热度按时间8zzbczxx1#
有时候,解引用是绝对必要的,比如在进行比较时:
在其他情况下,解引用是隐式的,比如在进行函数调用时:
通常这里少即是多,如果你不需要解引用,就不要去做。