当你应用count函数时，它应该像list_name.count(the_value_to_count)
但是当你在做e.count(item)的时候，e基本上是一个数字，而不是列表，集合，元组。
你可以像这样使用count函数。

emp = [] 
listLen = int(input("Enter the number of elements: "))
num = 1

for i in range(listLen):
  e = int(input("Enter element %d: " % num))
  num += 1
  emp.append(e)
  

for i in set(emp):
  #emp is a list. and i is the number. for which we have to count.    
  if emp.count(i) > 1:
    print(str(i)+" Has duplicate?: True")
  else:
    print(str(i)+" Has duplicate?: False")

• • 输出：**

Enter the number of elements: 6
Enter element 1: 99
Enter element 2: 42
Enter element 3: 63
Enter element 4: 42
Enter element 5: 56
Enter element 6: 99
56 Has duplicate?: False
42 Has duplicate?: True
99 Has duplicate?: True
63 Has duplicate?: False

• • 注意**list不按顺序，因为我在for循环中应用了set
• • 更新答复。**
• • 如果您只想检查列表是否包含重复项。**

使用计数器

from collections import Counter
emp = [] 
listLen = int(input("Enter the number of elements: "))
num = 1

for i in range(listLen):
  e = int(input("Enter element %d: " % num))
  num += 1
  emp.append(e)
  
a=Counter(emp)
if max(a.values()) > 1:
    print(" List Has duplicate?: True")
else:
    print(" List Has duplicate?: False")

• • 输出：**

Enter the number of elements: 5
Enter element 1: 2
Enter element 2: 3
Enter element 3: 1
Enter element 4: 2
Enter element 5: 5
List Has duplicate?: True