您可以使用BeautifulSoup和xml解析器来实现您的目标，只需选择所需的元素并通过.get()迭代ResultSet以提取属性值。

with open('filename.xml', 'r') as f:
    file = f.read() 
    soup = BeautifulSoup(file, 'xml')

示例

from bs4 import BeautifulSoup
import pandas as pd

xml = '''<?xml version="2.0" encoding="UTF-8" ?><timestamp="20220113">
<defintions>
    <defintion id="1" old_id="0">Lang</defintion>
    <defintion id="7" old_id="1">Eng</defintion>
'''
soup = BeautifulSoup(xml,'xml')

pd.DataFrame(
    [
        (e.get('id'),e.get('old_id'))
        for e in soup.select('defintion')
    ],
    columns = ['id','old_id']
)

输出

| | 身份证|旧标识|
| - ------|- ------|- ------|
| 无|1个|无|
| 1个|七|1个|

使用pythonBeautifulSoup，可以将.xml文件解析为BeatufulSoup对象，然后使用.findAll（'definitions '），然后循环遍历找到的标记并获得所需的值

object.findAll('defintions')

for defintion in defintions:
    old_id = defintions['old_id']
    id = defintions['id']

参考：https://www.crummy.com/software/BeautifulSoup/bs4/doc/https://linuxhint.com/parse_xml_python_beautifulsoup/

如果您有有效的XMLlike（时间戳标记不能有类似属性的值）：

<?xml version='1.0' encoding='utf-8'?>
<root timestamp='20220113'>
<defintions>
    <defintion id="1" old_id="0">Lang</defintion>
    <defintion id="7" old_id="1">Eng</defintion>
</defintions>
</root>

那么您可以使用pandas：

import pandas as pd

df = pd.read_xml('x89.xml', xpath='.//defintion')
print(df.to_string(index=False))

输出：

id  old_id defintion
  1       0      Lang
  7       1       Eng