输入3位数字no时出现问题，没有结果。输入123后，当2被检测为偶数时，如果用户输入7，则应显示173。但程序立即结束。这可能是最后一个0检查if块中的问题。但删除它也没有帮助。提前感谢！

// in 3 dig, check even dig., replace them with odd and disp.
import java.util.*;
public class p24123 {
    public static void main(String[] args) {
        int n,h,t,o,m,z=0,z1=0,z2=0,fn;
        Scanner ob = new Scanner(System.in);
        n=ob.nextInt();
        if(n>99&&n<1000){
            h= n/100;
            o=n%10;
            m=n/10;
            t=m%10;
            if(h%2==0){
               z=h;
                System.out.println("Enter the odd number you would like to replace the EVEN hundred's digit"+h+" with \n");
                z=ob.nextInt();
                if(z%2==0){
                    System.out.println("That's not odd. So we will keep the original digit in it's place");
                    z=h;
                }
                else if(t%2==0) {
                    System.out.println("Condition enter bokachpda");
                    z1 = t;
                    System.out.println("Enter the odd number you would like to replace the EVEN ten's digit" + t + " with \n");
                    z1 = ob.nextInt();
                    if (z % 2 == 0) {
                        System.out.println("That's not odd. So we will keep the original digit in it's place");
                        z1 = t;
                    }
                }
                else if(o%2==0){
                    z2=o;
                    System.out.println("Enter the odd number you would like to replace the EVEN one's digit"+h+" with \n");
                    z2=ob.nextInt();
                    if(z2%2==0){
                        System.out.println("That's not odd. So we will keep the original digit in it's place");
                        z2=o;
                    }
                }
                else if(2==2){
                    if(h<1||t<1||o<1||z<1||z1<1||z2<1){
                        System.out.println("Error");
                        System.exit(0);

                    }
                }
                fn=z*100+z1*10+z;

            }
        }
    }

}