rust 编写接受两种参数类型但执行相同操作的函数

hmtdttj4  于 2023-02-04  发布在  其他
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下面是我的src/main.rs文件:

use chrono_tz::Tz;
use chrono::FixedOffset;
use chrono::{NaiveDateTime, TimeZone, NaiveDate};

fn my_func(from_tz: Tz, ndt: NaiveDateTime){
    let res = from_tz.from_local_datetime(&ndt);
    println!("res: {:?}", res);
}

fn main() {
    let area_location: Tz = "UTC".parse().unwrap();
    let hour = 3600;
    let fixed_offset: FixedOffset = FixedOffset::east_opt(5 * hour).unwrap();
    let ndt = NaiveDate::from_ymd_opt(2038, 1, 19).unwrap().and_hms_opt(3, 14, 08).unwrap();
    my_func(area_location, ndt)
}

Cargo.toml

[package]
name = "tmp"
version = "0.1.0"
edition = "2021"

# See more keys and their definitions at https://doc.rust-lang.org/cargo/reference/manifest.html

[dependencies]
chrono = "0.4.23"
chrono-tz = "0.8.1"
regex = "1.7.1"

代码运行正常并打印

res: Single(2038-01-19T03:14:08UTC)

但是,我也可以将main的最后一行更改为my_func(fixed_offset, ndt),并将my_funcfrom_tz的类型更改为FixedOffset,代码仍然可以正常运行,打印

res: Single(2038-01-19T03:14:08+05:00)

在我的应用程序中,我不知道会收到Tz还是FixedOffset,无论哪种方式,我都希望将其传递给my_func,并在其中执行from_tz.from_local_datetime(&ndt)
如何让my_func接受TzFixedOffset

cbjzeqam

cbjzeqam1#

在本例中,所讨论的方法属于trait TimeZone,因此可以只接受绑定到该trait的泛型参数:

fn my_func<T: TimeZone>(from_tz: T, ndt: NaiveDateTime){
    let res = from_tz.from_local_datetime(&ndt);
    println!("res: {:?}", res);
}

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