我将使用一些虚拟的if/else if/else语句：

public static String convert(int minutes) {
  if(minutes < 60) {
    return String.format("%d mins", minutes);
  } else if(minutes % 60 == 0) { // No minutes - i.e. not a fractional hour.
    return String.format("%d hrs", minutes/60);
  } else if(minutes < 1440) { //1 day = 1440 minutes
    return String.format("%d hrs, %d mins", minutes/60, minutes%60);
  } else {
    return String.format("%d days", minutes / 1440);
  }
}

示例输出

System.out.println(convert(24));   //=> 24 mins
System.out.println(convert(120));  //=> 2 hrs
System.out.println(convert(84));   //=> 1 hrs, 24 mins
System.out.println(convert(2880)); //=> 2 days

嗯，这是可能的，我想通了，我为此感到自豪！：）注意，你可以很容易地添加任何其他值，而不需要改变方法本身，只需要改变这两个数组中的值。例如，如果“年”对你来说不够，你可以添加“十年”和“世纪”...
此代码还在末尾添加“s”字母，如果有多个输出值。

public class SuperMinutesChangerClass {
    public static int[] barriers = {1, 60, 60*24, 60*24*7, 60*24*365, Integer.MAX_VALUE};
    public static String[] text = {"min", "hr", "day", "week", "year"};

    public static String minutesToHumanReadable(int minutes){
        String toReturn = "";
        for (int i = 1; i < barriers.length; i++) {
            if (minutes < barriers[i]){
                int ammount = (minutes/barriers[i-1]);
                toReturn = ">" + (ammount) + " " + text[i-1];
                if (ammount > 1){
                    toReturn += "s";
                }
                break;
            }
        }
        return toReturn;
    }         
}

样品输入：

public static void main(String[] args) {
        System.out.println(minutesToHumanReadable(10));
        System.out.println(minutesToHumanReadable(60));
        System.out.println(minutesToHumanReadable(61));
        System.out.println(minutesToHumanReadable(121));
        System.out.println(minutesToHumanReadable(8887));
        System.out.println(minutesToHumanReadable(9999743));
    }

输出为：

>10 mins
>1 hr
>1 hr
>2 hrs
>6 days
>19 years

也许这能帮你

private static final int MINUTES_PER_HOUR = 60;
private static final int MINUTES_PER_DAY = MINUTES_PER_HOUR * 24;

public String minutesToHumanReadable(long minutes) {
    if (minutes > MINUTES_PER_DAY) {
        return String.format("> %d days", minutes / MINUTES_PER_DAY);
    } else if (minutes > MINUTES_PER_HOUR) {
        return String.format("> %d hours", minutes / MINUTES_PER_HOUR);
    }

    return String.format("%d minutes", minutes);
}

约书亚·品特和阿诺德·德诺耶尔改进了答案。

fun convertMinutesToHumanReadable(minutes: Int, context: Context): String {
    return if (minutes < 60) {
        "$minutes ${context.resources.getQuantityString(R.plurals.minutes_abbrev, minutes)}"
    } else if (minutes % 60 == 0 && minutes < 1440) {
        val hours1 = minutes / 60
        "$hours1 ${context.resources.getQuantityString(R.plurals.hours_abbrev, hours1)}"
    } else if (minutes < 1440) {
        val hours1 = minutes / 60
        val minutes1 = minutes % 60
        "$hours1 ${
            context.resources.getQuantityString(
                R.plurals.hours_abbrev, hours1
            )
        }, $minutes1 ${
            context.resources.getQuantityString(
                R.plurals.minutes_abbrev, minutes1
            )
        } "
    } else if (minutes % 1440 == 0) {
        val days1 = minutes / 1440
        "$days1 ${context.resources.getQuantityString(R.plurals.days, days1)}"
    } else {
        val days1 = minutes / 1440
        "$days1 ${context.resources.getQuantityString(R.plurals.days, days1)}, ".plus(
            convertMinutesHumanReadable(minutes % 1440, context)
        )
    }
}

并将其添加到res/values/strings.xml文件中

<plurals name="minutes_abbrev">
        <item quantity="one">min</item>
        <item quantity="other">mins</item>
    </plurals>
    <plurals name="hours_abbrev">
        <item quantity="one">hr</item>
        <item quantity="other">hrs</item>
    </plurals>
    <plurals name="days">
        <item quantity="one">day</item>
        <item quantity="other">days</item>
    </plurals>

通过这种方式，它将根据数量显示单数或复数，并支持值 大于一天。例如：2天8小时23分钟或1天2小时1分钟