Flutter应用程序运行无法调用空对象上的toInteger()方法

7hiiyaii  于 2023-02-05  发布在  Flutter
关注(0)|答案(2)|浏览(331)

我是Flutter的新手,我刚刚在GitHub上克隆了一个项目,我必须处理它。因此,在我的android studio中运行该项目时,会出现以下错误:
失败:生成失败,出现异常。

  • 其中:构建文件"C:\用户\19ngu\AndroidStudioProjects\damufasta\android\app\build.gradle"行:29
  • 出了什么问题:评估项目":app"时出现问题。

无法对空对象调用toInteger()方法
我已经解决了依赖关系,并按照检查其他响应的指示将项目SDK和模块指向最新的API。因此,我希望它能成功运行。
这是app\build. gradle文件的内容:

def localProperties = new Properties()
def localPropertiesFile = rootProject.file('local.properties')
if (localPropertiesFile.exists()) {
    localPropertiesFile.withReader('UTF-8') { reader ->
        localProperties.load(reader)
    }
}

def flutterRoot = localProperties.getProperty('flutter.sdk')
if (flutterRoot == null) {
    throw GradleException("Flutter SDK not found. Define location with flutter.sdk in the local.properties file.")
}

def flutterVersionCode = localProperties.getProperty('flutter.versionCode')
if (flutterVersionCode == null) {
    flutterVersionCode = '1'
}

def flutterVersionName = localProperties.getProperty('flutter.versionName')
if (flutterVersionName == null) {
    flutterVersionName = '1.0'
}

apply plugin: 'com.android.application'
apply plugin: 'kotlin-android'
apply from: "$flutterRoot/packages/flutter_tools/gradle/flutter.gradle"

android {
    compileSdkVersion localProperties.getProperty('flutter.compileSdkVersion').toInteger()
    ndkVersion flutter.ndkVersion

    compileOptions {
        sourceCompatibility JavaVersion.VERSION_1_8
        targetCompatibility JavaVersion.VERSION_1_8
    }

    kotlinOptions {
        jvmTarget = '1.8'
    }

    sourceSets {
        main.java.srcDirs += 'src/main/kotlin'
    }

    defaultConfig {
        // TODO: Specify your own unique Application ID (https://developer.android.com/studio/build/application-id.html).
        applicationId "com.example.damufasta"
        // You can update the following values to match your application needs.
        // For more information, see: https://docs.flutter.dev/deployment/android#reviewing-the-build-configuration.
        minSdkVersion localProperties.getProperty('flutter.minSdkVersion').toInteger()
        targetSdkVersion localProperties.getProperty('flutter.targetSdkVersion').toInteger()
        versionCode flutterVersionCode.toInteger()
        versionName flutterVersionName
    }

    buildTypes {
        release {
            // TODO: Add your own signing config for the release build.
            // Signing with the debug keys for now, so `flutter run --release` works.
            signingConfig signingConfigs.debug
        }
    }
}

flutter {
    source '../..'
}

dependencies {
    implementation "org.jetbrains.kotlin:kotlin-stdlib-jdk7:$kotlin_version"
}
km0tfn4u

km0tfn4u1#

将最小sdk设置为21:
minSdkVersion = 21第44行构建版本.gradle

f0brbegy

f0brbegy2#

如果发生这种情况,响应者提到的一个可能的问题是www.example.com文件中缺少minSdkVersion的值local.properties。
因此,首先检查这些值是否存在,如果不存在,则添加它们。
如果存在,则确保minSdkVersion为21。
这对我很有效。

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