我将json转换为对象并得到此错误
Newtonsoft.Json.JsonSerializationException: 'Error converting value "{"mid":"2","phone":"0965403801","requestId":"1585970510.732827","bankHubToken":"eyJ0aW1lc3RhbXAiOiIxNjMzNDE4NzgyNzQ0IiwidG9rZW4iOiI5NWJmYWM3OC00YmY3LTQyM2MtYjAxNS00NTNjMjkzYzk1ZWEiLCJzaWduIjoiLzVrcTg2dWdReFUvQ1daWCt2TERSaGhvaXN1VC9hS1JpejEwUGtTU0dxUVx1MDAzZCJ9","userName":"1392H46"}" to type 'OBBE.DGBIZ.API.Model.DataFieldUploadFile'. Path '', line 1, position 305.'
我的代码
var data = context.ActionArguments["data"];
if (data == null)
{
context.Result = new OkObjectResult(
new ErrorResponseMessage() { context = new ContextResponse(false, new List<string>() { APPID, HANDER_ERRORCODE.ERR_REQUEST_CONTENT.ToString(), "Request null" }, new ContextRequest("", ""), ResultConstants.ERROR_CODE_FAIL, "Request null") });
return;
}
try
{
String x = JsonConvert.SerializeObject(data);
data = JsonConvert.DeserializeObject<DataFieldUploadFile>(JsonConvert.SerializeObject(data));
}
我的班级
public class DataFieldUploadFile
{
public String? mid { get; set; }
public String? requestId { get; set; }
public String? phone { get; set; }
public String? bankHubToken { get; set; }
public String? userName { get; set; }
}
我试过了,但是不行。
1条答案
按热度按时间h5qlskok1#
试试这个
如果数据为空,则意味着数据可能已经是一个JSON字符串,并尝试对其进行双重序列化。
所以你真的需要这个代码