python 创建用于掷骰子的不和谐机器人时出现问题

vql8enpb 于 2023-02-11 发布在 Python

关注(0)|答案(1)|浏览(117)

This is my first trying creating a discord bot. I want it to work like this:
User:
/roll 2d20+4
Then my bot will roll 2d20, save the sum and the bigger. Finally, it will print like this:
Output:
Bigger: 16+4=20 | Sum: 23+4=27.
This is the code I have:

import hikari
import lightbulb
import random

disc_token="..."
server_id="..."

bot=lightbulb.BotApp(
    token=disc_token,
    default_enabled_guilds=int(server_id)
)


@bot.command
@lightbulb.command('roll',"Role dados (exemplo: 2d20+5)")
@lightbulb.implements(lightbulb.SlashCommand)

async def roll(ctx,play):
    die_split=play.split("d")
    final_split=die_split[1].split("+")
    n_die=int(die_split[0])
    die=int(final_split[0])
    extra=int(final_split[1])
    play=[n_die,die,extra]
    best_roll=0
    sum_roll=0
    for i in range(n_die):
        actual_roll=random.randint(1,die)
        sum_roll=sum_roll+actual_roll
        if(actual_roll>best_roll):
            best_roll=actual_roll
    sum_roll=sum_roll+extra
    extra_roll=best_roll+extra
    play_print='Bigger: '+str(best_roll)+'+'+str(extra)+'='+str(extra_roll)+' | Sum: '+str(sum_roll)
    
    await ctx.respond(play_print)

bot.run()

What is happening:
The bot is working (I tested some basic commands, like "Hello World" and works fine), but when I try to run the /roll command, for the discord user it shows: "! The app did not answered". At my terminal, the error was displayed like this:
Traceback (most recent call last): File "C:\Users\MateusRochaQSOFT\AppData\Local\Packages\PythonSoftwareFoundation.Python.3.10_qbz5n2kfra8p0\LocalCache\local-packages\Python310\site-packages\lightbulb\app.py", line 1163, in invoke_application_command await context.invoke() File "C:\Users\MateusRochaQSOFT\AppData\Local\Packages\PythonSoftwareFoundation.Python.3.10_qbz5n2kfra8p0\LocalCache\local-packages\Python310\site-packages\lightbulb\context\base.py", line 328, in invoke await self.command.invoke(self) File "C:\Users\MateusRochaQSOFT\AppData\Local\Packages\PythonSoftwareFoundation.Python.3.10_qbz5n2kfra8p0\LocalCache\local-packages\Python310\site-packages\ligh raise new_exc lightbulb.errors.CommandInvocationError: An error occurred during command 'roll' invocation
What could be wrong?

python

来源：https://stackoverflow.com/questions/75411095/problem-creating-a-discord-bot-for-rolling-dice

1条答案

按热度按时间

2ul0zpep1#

我认为你在使用lightbulb包时定义了错误的选项。你必须使用@lightbulb.option装饰器来定义选项，然后才能通过ctx.options访问它们。其中选项的名称是你能得到的属性。

@bot.command
@lightbulb.option("play", "dice roll")
@lightbulb.command('roll',"Role dados (exemplo: 2d20+5)")
@lightbulb.implements(lightbulb.SlashCommand)
async def roll(ctx):
    play = ctx.options.play
    die_split = play.split("d")
    final_split = die_split[1].split("+")
    n_die = int(die_split[0])
    die = int(final_split[0])
    extra = int(final_split[1])
    play = [n_die,die,extra]
    best_roll = 0
    sum_roll = 0
    for i in range(n_die):
        actual_roll = random.randint(1, die)
        sum_roll = sum_roll + actual_roll
        if actual_roll > best_roll:
            best_roll = actual_roll
    sum_roll = sum_roll + extra
    extra_roll = best_roll + extra
    play_print = f"Bigger: {best_roll} + {extra} = {extra_roll} | Sum: {sum_roll}"
    await ctx.respond(play_print)

bot.run()

可在此处的文档中找到。您可以使用ctx.options.play访问play变量。
我还格式化了代码以使用PEP8 formatting，并且使用f-strings代替了您正在进行的字符串连接。
您还可以使用@lightbulb.command中的pass_options参数将所有定义的选项（通过装饰器）作为关键字参数传递。
就像这样：

@bot.command
@lightbulb.option("play", "dice roll")
@lightbulb.command('roll',"Role dados (exemplo: 2d20+5)", pass_options=True)
@lightbulb.implements(lightbulb.SlashCommand)
async def roll(ctx, play):

这样就不需要执行play = ctx.options.play。

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python 创建用于掷骰子的不和谐机器人时出现问题

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